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rusak2 [61]
3 years ago
6

Carl has a piece of string that is 14 inches long. What is the length of the string in centimeters? Show your work.

Mathematics
1 answer:
sukhopar [10]3 years ago
6 0
14 in = 35. 56
multiple the length by 2.54
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during a softball game kay hit a fly ball the function f(x) = -16t^2 + 64t + 4 describes the height of the softball in feet. mak
STatiana [176]
<h2>Hello!</h2>

The graph is attached.

To graph a parabola we need to know the following:

- If the parabola is open upwards or downwards

- They axis intercepts (if they exist)

- The vertex position (point)

We are given the function:

f(t)=-16t^{2}+64t+4

Where,

a=-16\\b=64\\c=4

For this case, the coefficient of the quadratic term (a) is negative, it means that the parabola opens downwards.

Finding the axis interception points:

Making the function equal to 0, we can find the x-axis (t) intercepts, but since the equation is a function of the time, we will only consider the positive values, so:

f(t)=-16t^{2}+64t+4\\0=-16t^{2}+64t+4\\-16t^{2}+64t+4=0

Using the quadratic equation:

\frac{-b+-\sqrt{b^{2}-4ac } }{2a}=\frac{-64+-\sqrt{64^{2}-4*-16*4} }{2*-16}\\\\\frac{-64+-\sqrt{64^{2}-4*-16*4} }{2*-16}=\frac{-64+-\sqrt{4096+256} }{-32}\\\\\frac{-64+-\sqrt{4096+256} }{-32}=\frac{-64+-(65.96) }{-32}\\\\t1=\frac{-64+(65.96) }{-32}=-0.06\\\\t2=\frac{-64-(65.96) }{-32}=4.0615

So, at t=4.0615 the height of the softball will be 0.

Since we will work only with positive values of "x", since we are working with a function of time:

Let's start from "t" equals to 0 to "t" equals to 4.0615.

So, evaluating we have:

f(0)=-16(0)^{2}+64(0)+4=4\\\\f(1)=-16(1)^{2}+64(1)+4=52\\\\f(2)=-16(2)^{2}+64(2)+4=68\\\\f(3)=-16(3)^{2}+64(3)+4=52\\\\f(4.061)=-16(4.0615)^{2}+64(4.0615)+4=0.0034=0

Finally, we can conclude that:

- The softball reach its maximum height at t equals to 2. (68 feet)

- The softball hits the ground at t equals to 4.0615 (0 feet)

- At t equals to 0, the height of the softball is equal to 4 feet.

See the attached image for the graphic.

Have a nice day!

3 0
3 years ago
Solve the attached question<br><br>#yohaniJaman<br><br><br><br>​
aksik [14]

HETY is a parallelogram.

HT and EY are diagonals. We know that diagonals divides the parallelogram into two equal parts.

So ar(HET) = ar(HTY)

And, ar(HEY) = ar(EYT) now, in AHET, diagonal EY bisects the line segment HT and also the AHET,

∴ar(AHOE) = ar(AEOT)

Similarly in AETY

ar(ΔΕΟΤ) = ar(ΔΤΟΥ)

And in AHTY,

ar(ATOY) = ar(AHOY)

That means diagonals in parallelogram divides it into four equal parts.

Hence Proofed.

5 0
2 years ago
Evaluate the numerical expression 2+65 + 7*3=
riadik2000 [5.3K]
2 + 65 + 7 × 3
= 2 + 65 + 21
= 67 + 21
= 88

answer is 88
7 0
3 years ago
Read 2 more answers
In the equation y = 2π^x, 2 is the ______ and π is the ______.
olga2289 [7]

Answer:

pi(π) is the constant and x is the variable since pi is a numerical value and x can change according to the equation given.

Step-by-step explanation:

8 0
3 years ago
Evaluate each expression |-16| -|-1|
Maslowich

Understanding the Absolute Value.

First, know what the absolute value is.

The absolute value is the value that determines how far the value is from 0.

For example, The absolute value of -5 is far from 0 5 units. Therefore the absolute value of -5 equals 5.

Basic Absolute Value Defines

| a | = a

- | a | = -a

| - a | = a

Back to the question. To evaluate those expressions, we use the defines of absolute value.

|-16| = 16

|-1| = 1

16-(1)

Then remove the brackets. 16 - 1 = 15

Therefore, the answer is 15.

<em>The</em><em> </em><em>answer</em><em> </em><em>above</em><em> </em><em>is</em><em> </em><em>when</em><em> </em><em>being</em><em> </em><em>subtracted</em><em> </em><em>and</em><em> </em><em>evaluated</em><em> </em><em>from</em><em> </em><em>both</em><em> </em><em>16</em><em>-</em><em>1</em>

<em>Evaluating</em><em> </em><em>for</em><em> </em><em>each</em><em> </em><em>expressions</em><em> </em><em>would</em><em> </em><em>be</em>

<em>|</em><em>-</em><em>16</em><em>|</em><em> </em><em>=</em><em> </em><em>16</em>

<em>-</em><em>|</em><em>-</em><em>1</em><em>|</em><em> </em><em>=</em><em> </em><em>-</em><em>1</em>

4 0
3 years ago
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