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katen-ka-za [31]
3 years ago
7

What is the sum of the linear expressions?

Mathematics
1 answer:
madam [21]3 years ago
3 0
8n+4 because you have to add it all up
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Rewrite the fractions 3/4 and 7/10 as fractions with a least common denominator.
liraira [26]

Answer:

4.75

Step-by-step explanation:

Can you tell me if right and can you give me brainliest??

3 0
3 years ago
Evaluate each expression. 3^-2
Rus_ich [418]
9 is the answer negatives cancel out creating positve
7 0
3 years ago
Read 2 more answers
The normal yearly growth of a plant is 60 inches. The normal growth was ten inches more than twice the amount of last year. What
Usimov [2.4K]

The growth of the plant last year was 25 inches if the normal growth was ten inches more than twice the amount of last year.

<h3>What is linear equation?</h3>

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

The normal yearly growth of a plant is 60 inches.

Let's suppose the growth of the plant last year was x

The normal growth was ten inches more than twice the amount of last year.

From the above statement:

10 + 2x = 60

2x = 50

x = 25 inches

Thus, the growth of the plant last year was 25 inches if the normal growth was ten inches more than twice the amount of last year.

Learn more about the linear equation here:

brainly.com/question/11897796

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4 0
2 years ago
A population of bees is decreasing. The population in a particular region this year is 1,250. After 1 year, it is estimated tha
8_murik_8 [283]
To model this situation, we are going to use the decay formula: A=Pe^{rt}
where 
A is the final pupolation
P is the initial population 
e is the Euler's constant
r is the decay rate 
t is the time in years

A. We know for our problem that the initial population is 1,250, so P=1250; we also know that after a year the population is 1000, so A=1000 and t=1. Lets replace those values in our formula to find r:
A=Pe^{rt}
1000=1250e^{r}
e^{r}= \frac{1000}{1250}
e^{r}= \frac{4}{5}
ln(e^{r})=ln( \frac{4}{5} )
r=ln( \frac{4}{5} )
r=-02231

Now that we have r, we can write a function to model this scenario:
A(t)=1250e^{-0.2231t}.

B. Here we are going to use a graphing utility to graph the function we derived in the previous point. Please check the attached image.

C. 
- The function is decreasing
- The function doe snot have a x-intercept 
- The function has a y-intercept at (0,1250)
- Since the function is decaying, it will have a maximum at t=0: 
A(0)=1250e^{(-0.2231)(0)
A_{0}=1250e^{0}
A_{0}=1250
- Over the interval [0,10], the function will have a minimum at t=10:
A(10)=1250e^{(-0.2231)(10)
A_{10}=134.28

D. To find the rate of change of the function over the interval [0,10], we are going to use the formula: m= \frac{A(0)-A(10)}{10-0}
where 
m is the rate of change 
A(10) is the function evaluated at 10
A(0) is the function evaluated at 0
We know from previous calculations that A(10)=134.28 and A(0)=1250, so lets replace those values in our formula to find m:
m= \frac{134.28-1250}{10-0}
m= \frac{-1115.72}{10}
m=-111.572
We can conclude that the rate of change of the function over the interval [0,10] is -111.572.

7 0
3 years ago
Solve the equation -9v-9=-27 for v.
Nikolay [14]

Answer:

v=2

Step-by-step explanation:

-9v-9=-27

add nine to both sides

-9v-9+9=-27+9

simplify

-9v=-18

divide both sides by -9

-9v/-9   -18/-9

simplify y=2

hope this helps :) have a nice day !!

4 0
3 years ago
Read 2 more answers
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