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NeX [460]
3 years ago
13

A diamond retailer buys a ring from his supplier for $875.He marks up the price 110% to sell in his store.What is the selling pr

ice of the diamond with a 6% sales tax?
Mathematics
1 answer:
Gennadij [26K]3 years ago
4 0

A diamond retailer buys a ring from his supplier for $875.He marks up the price 110% to sell in his store.What is the selling price of the diamond with a 6% sales tax?

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What is the future value for a savings account that had $825 deposited in it for 10 years. The
Goshia [24]

Answer:

The answer is 2145$

Step-by-step explanation:

825×0.04=33

Once every quarter of a year means the number of years × 4 = 10×4=40

So

33×40 =1320$

1320+825=2145$

7 0
2 years ago
1. Write the form of the partial fraction decomposition of the rational expression. Do not solve for the constants.
german

Answer:

Step-by-step explanation:

1.

To write the form of the partial fraction decomposition of the rational expression:

We have:

\mathbf{\dfrac{8x-4}{x(x^2+1)^2}= \dfrac{A}{x}+\dfrac{Bx+C}{x^2+1}+\dfrac{Dx+E}{(x^2+1)^2}}

2.

Using partial fraction decomposition to find the definite integral of:

\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}dx

By using the long division method; we have:

x^2-8x-20 | \dfrac{2x}{2x^3-16x^2-39x+20 }

                  - 2x^3 -16x^2-40x

                 <u>                                         </u>

                                            x+ 20

So;

\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x+\dfrac{x+20}{x^2-8x-20}

By using partial fraction decomposition:

\dfrac{x+20}{(x-10)(x+2)}= \dfrac{A}{x-10}+\dfrac{B}{x+2}

                         = \dfrac{A(x+2)+B(x-10)}{(x-10)(x+2)}

x + 20 = A(x + 2) + B(x - 10)

x + 20 = (A + B)x + (2A - 10B)

Now;  we have to relate like terms on both sides; we have:

A + B = 1   ;   2A - 10 B = 20

By solvong the expressions above; we have:

A = \dfrac{5}{2}     B =  \dfrac{3}{2}

Now;

\dfrac{x+20}{(x-10)(x+2)} = \dfrac{5}{2(x-10)} + \dfrac{3}{2(x+2)}

Thus;

\dfrac{2x^3-16x^2-39x+20}{x^2-8x-20}= 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)}

Now; the integral is:

\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx =  \int \begin {bmatrix} 2x + \dfrac{5}{2(x-10)}+ \dfrac{3}{2(x+2)} \end {bmatrix} \ dx

\mathbf{\int \dfrac{2x^3-16x^2-39x+20}{x^2-8x-20} \ dx =  x^2 + \dfrac{5}{2}In | x-10|\dfrac{3}{2} In |x+2|+C}

3. Due to the fact that the maximum words this text box can contain are 5000 words, we decided to write the solution for question 3 and upload it in an image format.

Please check to the attached image below for the solution to question number 3.

4 0
3 years ago
The length of a string in yards is a function f(n) of the length n in inches. Write a function rule for this situation
igor_vitrenko [27]

Answer:

f(n) = n/36

Step-by-step explanation:

The length of a string is given in yards, is a function f(n) of the length n in inches.

We have to write a function rule for this situation.

∵ 36 inches = 1 yard

∴ 1 inch = 1/36 (yard)

∴ n inches = n/36

and function representing the length will be

f(n) = n/36

4 0
3 years ago
Read 2 more answers
A store sells cheese in half a pound package a recipe calls fpr 1.72 pound of cheese how many packages does the chef need
Sedbober [7]

Answer:

4 packages

Step-by-step explanation:

Since the store sells by 1/2 packages, we have to round 1.72 UP to 2.00. Then we multiply 1/2pound by 4= 2.00 pounds

4 0
3 years ago
Natalie won 91 super bouncy balls playing
Andru [333]
30 students. do this. take 91/3 and get 30 with one leftover. so, there are 30 kids in her math class
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3 years ago
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