The equation of line passing through the point P(-8,0) that is perpendicular to the line y=-3 is y=0 which can be found out from slope intercept formula.
It is given to us that -
The point is P(-8,0)
The line is represented as y=-3
The point P is perpendicular to the given line.
We have to find out the equation of the line passing through P which is perpendicular to the given line.
We know that the equation of a line is given by -
y = mx + c
where, (x, y) = coordinates of the point
m = slope of the line
c = a constant
Comparing this with the equation of the given line, we have
m=0 and c =-3
This implies that the slope of the perpendicular is also equal to 0.
The slope intercept formula for the perpendicular line can be represented as -
y = mx + c
Using the coordinates of P(-8,0), we have
0 = 0*(-8) +c
=> c = 0.
Thus, the equation of line passing through the point P(-8,0) that is perpendicular to the line y=-3 is y=0.
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To get 20/10 as a mixed number you would have to take 20 and divide it by 10. Once you do that your answer should be 2.
Answer: Let the smaller angle be x. Then the other angle will be 2x+20. Since the two angles are supplementary, their sum will be 180 degrees
Step-by-step explanation:
Answer:
C. Acute and Isosceles
Step-by-step explanation:
Acute means the angles are less than 90 degrees. All of the triangles angles are less than 90 degrees.
Isosceles means they have 2 sides of equal length. In the triangle, there are 2 sides with the length of 6 in, making this an isosceles triangle
Answer:
-1/10
Step-by-step explanation:
