Domain is the entire span left to right (on the x-axis) that the graph is on. Since the graph goes from x=-4 and ends at x=4, the domain would be from -4 to 4. The circle at -4 is open, so it does not include the point at -4, just everything leading up to it. So, the domain would be
The range is similar, it is the entire span that the graph goes up and down (on the y-axis). The graph starts at the bottom at y=-2, and ends at y=5. The bottom point (4,-2) is closed, so the graph includes that point, and the top point (-4,5) is open and doesn't include the point. Therefore, the range would be
The first and crucial thing we want to take notice is that the lines DF and EG intersect at point H which creates 4 different triangles in the rhombus. The innermost angles of DGH and EFH are vertical angles and vertical angles are congruent. So if the angles of the triangles are congruent than the triangles themselves are congruent. This is supported by the vertical angles theorem.
Answer:
x = - 
, x = 
Step-by-step explanation:
The absolute value function always gives a positive value, however, the expression inside can be positive or negative, that is
- 3x + 16 = 18 or -(- 3x + 16) = 18
Solving
- 3x + 16 = 18 ( subtract 16 from both sides )
- 3x = 2 ( divide both sides by - 3 )
x = -
or
-(- 3x + 16) = 18
3x - 16 = 18 ( add 16 to both sides )
3x = 34 ( divide both sides by 3 )
x = 
As a check
Substitute these values into the left side of the equation and if equal to the right side then they are the solutions.
| - 3(- ) + 16 | = | 2 + 16 | = | 18 | = 18 ← True
| - 3( ) + 16 | = | - 34 + 16 | = | - 18 | = 18 ← True
Thus x = - and x = are the solutions
Answer:
(0,0)
Step-by-step explanation:
The coordinates of C now are (-7,-5).
Moving C -3 on the x-axis will move -7 - 3 = -10. C is now located on (-10,-5).
Moving C +5 on the y-axis will move -5 + 5 = 0. C is now located on (-10,0).
Moving C on the y-axis +10 will move -10 + 10 = 0. C is now located on (0,0).
C is translated to (0,0).
<h2>Vertical distance gained from takeoff is 493.72 ft</h2>
Step-by-step explanation:
Refer the figure.
Horizontal distance = AB = 2800 ft
Angle = ∠B = 10°
We need to find AC that is h.
We have
Vertical distance gained from takeoff = 493.72 ft
