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zalisa [80]
3 years ago
8

Sorry this question doesn’t give 100 points, I don’t have that many points to do 100 again. So, take these points and I will mar

k brainliest! Have a great day, and stay safe. If you ever have any symptoms, make sure to self quarantine yourself and schedule an appointment with a doctor through phone call. Make sure to wear a mask whenever you are outside, too!
Mathematics
2 answers:
Rzqust [24]3 years ago
6 0

why did the answer get deleted lol but hey free points thx

NNADVOKAT [17]3 years ago
3 0

Answer:

oh hi

Step-by-step explanation:

thx

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Can someone please explain to me how I would do this, I cannot figure out how to do this equation at all!!
Marina86 [1]

Answer:

First, do 4x*4x. then,16x*16x. next, 64x*64x. and,256x*256x. answer:1024x. Divide 1024x by 8x. answer to that is 128.

4 0
3 years ago
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What is the y-coordinate for the solution of the system of equations below? 7y+5x=19 3y+5x=7
RoseWind [281]
I would go about solving this by elimination because the x variables are already the same so all you would have to do is change one equation to the opposite signs and add them, so it would look like:

7y + 5x = 19
+ -3y - 5x = -7
-------------------
4y=12
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7 0
3 years ago
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How many years will it take for a sum of money to double at 10% compounded annually
Bond [772]

Answer:

t=7.27 years

Step-by-step explanation:

Let the money be p and t will be the number of years that will be needed for the money to get double.

ATQ, 2p=p*(1+0.1)^t

2=(1.1)^t

log(2)/log(1.1)=t, t=7.27

5 0
3 years ago
Solve for y: 2(3y 5)=3(5y 13)
ELEN [110]
Assuming the spaces mean plus (+):

2(3y+5) = 3(5y+13)
6y+10 = 15y+39
10 = 9y+39
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Therefore, y = -29/9 or -3.22
3 0
3 years ago
The temperature reading from a thermocouple placed in a constant-temperature medium is normally distributed with mean μ, the act
cluponka [151]

Answer: 0.3061.

Step-by-step explanation:

Given : The temperature reading from a thermocouple placed in a constant-temperature medium is normally distributed with mean \mu, the actual temperature of the medium, and standard deviation \sigma.

Let X be the random variable that represents the reading of the thermometer.

Confidence level : =95\%

We know that the z-value for 95% confidence interval is 1.96.

Then, we have

-1.96      z=\dfrac{X-\mu}{\sigma}

\Rightarrow\ -1.96\sigma  

But all readings are within 0.6° of \mu.

So, 1.96\sigma=0.6  

\Rightarrow\ \sigma=\dfrac{0.6}{1.96}=0.30612244898\approx0.3061

Hence, the required standard deviation will be  

7 0
3 years ago
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