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3 years ago

Will rate you brainliest

Mathematics

1 answer:

GREYUIT [131]3 years ago

5 0

Answer:

$\frac{11x}{3y}$

Step-by-step explanation:

$\frac{7x}{3y} + \frac{12x}{9y}$

Make both a single fraction by adding together.

$\frac{3(7x) + 1(12x)}{9y}$

$\frac{21x + 12x}{9y}$

$\frac{33x}{9y}$

Simplify

$\frac{3(11)x}{3(3y)}$

$\frac{11x}{3y}$

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8 less than one third of x is y.

Andre45 [30]

1/3x - 8 = y <== ur equation

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3 years ago

Read 2 more answers

How do I solve this math problem?

Nat2105 [25]

Answer: 4x² + 4x - 2 - $\frac{3}{2x+3}$

Step-by-step explanation:

You can use either synthetic or long division. I am using synthetic division:

2x + 3 = 0 ⇒ x = $-\frac{3}{2}$

$-\frac{3}{2}$ | 4 10 4 -6

| ↓ -6 -6 3

4 4 -2 -3 ← -3 is the remainder

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4x² +4x -2 ← factored polynomial

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3 years ago

A wrestling match has eliminations each round. The table below shows the number of wrestlers in each of the first 4 rounds of th

AlladinOne [14]

$\bf \begin{array}{lllll}
round(x)&\boxed{1}&2&3&\boxed{4}\\\\
wrestlers[f(x)]&\boxed{64}&32&18&\boxed{9}
\end{array}
\\\\\\
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ f(x_2)}}-{{ f(x_1)}}}{{{ x_2}}-{{ x_1}}}\impliedby 
\begin{array}{llll}
average\ rate\\
of\ change
\end{array}\\\\
-------------------------------\\\\
f(x)= \qquad 
\begin{cases}
x_1=1\\
x_2=4
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55 over 3, or 55 wrestlers for every 3 rounds, but the wrestlers value is negative, thus 55 "less" wrestlers for every 3 rounds on average.

6 0

3 years ago

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What is three hundred twenty-five thousand, one hundred eight written standard form?

Evgesh-ka [11]

Answer:

325108

Step-by-step explanation:

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3 years ago

A person borrowef Rs 16000 from a bank at 12.5% pet annum simple intrest and lent the whole amount to shopkeeper at the sam rate

r-ruslan [8.4K]

Answer:

The amount he gains in 2 years is Rs. 250

Step-by-step explanation:

The parameters of the amount borrowed from the bank are;

The amount borrowed, P = Rs. 16,000

The interest rate of the amount borrowed, R = 12.5%

The number of years, T = 2 years

The simple interest, I = (P × R × T)/100 = (Rs. 16,000 × 12.5 × 2)/100 = Rs. 4,000

The total amount the person is to pay bank to the bank = P + I = Rs. 16,000 + Rs. 4,000 = Rs. 20,000

The parameters of the amount lent to the shopkeeper are;

The amount lent, P = Rs. 16,000

The compound interest rate of the amount lent, R = 12.5%

The number of years, T = 2 years

The amount he receives from the shopkeeper after 2 years, A = P·(1 + R/n)^(n × T) = Rs. 16,000 × (1 + 0.125/1)^(1 × 2) = Rs. 20,250

The amount he gains in 2 years = The amount he receives from the shop keeper - The amount he gives to the bank = Rs. 20,250 - Rs. 20,000 = Rs. 250

The amount he gains in 2 years = Rs. 250.

8 0

2 years ago