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3 years ago

What is an equation of the line that passes through the points (-2,7) and (1, -8)?

Mathematics

1 answer:

ruslelena [56]3 years ago

3 0

I’m just trying to ask another question .

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Find the exact value in the picture above

fomenos

Answer:

A and B

Step-by-step explanation:

You can take a look at a unit circle to find the solution to this problem (see below).

$\cos^{-1}\left( \dfrac{\sqrt{2}}{2} \right)= \\\\\\\pm \dfrac{\pi}{4}= \\\\\\\dfrac{\pi}{4}, \dfrac{7\pi}{4}$

Hope this helps!

7 0

2 years ago

5x + 5 = x + 45<br><br> PLEASE HELP

Ostrovityanka [42]

$5x+5=x+45$

We'd rather not have x on both sides of the equation when trying to solve this. To eliminate the x on the right side, subtract both sides by x.

$5x+5-x=x+45-x$
$4x+5=45$

Let's get eliminate the "5" on the left side. Subtract both sides by 5.

$4x+5-5=45-5$
$4x=40$

To finish this, divide both sides by 4.

$4x \div 4=40 \div 4$
$x=10$

That is the answer. Hope this helps! :)

5 0

3 years ago

What is the product of 2a-7/a* 3a^2/2a^2-11a+14

Vera_Pavlovna [14]

Answer:

B. 3a/a-2

Step-by-step explanation: according to e2020

8 0

3 years ago

A cell phone company charges $40 per month for unlimited calling, and $0.20 per text message sent. If t represents the number of

sergejj [24]

Answer:

Step-by-step explanation:

40 per month + 0.20 per text(t)

40 + 0.2t....no parenthesis needed

4 0

2 years ago

The equation 2x^2 – 8x = 5 is rewritten in the form of 2(x – p)^2 + q = 0. what is the value of q?

QveST [7]

Answer:

q = -13

Step-by-step explanation:

The given equation is:

$2x^{2}-8x=5$

Taking 2 as common from left hand side, we get:

$2(x^{2}-4x)=5\\\\2[x^{2} - 2(x)(2)]=5$

The square of difference is written as:

$(a-b)^{2}=a^2 - 2ab + b^{2}$ Equation 1

If we compare the given equation from previous step to formula in Equation 1, we note that we have square of first term(x), twice the product of 1st term(x) and second term(2) and the square of second term(2) is missing. So in order to complete the square we need to add and subtract square of 2 to right hand side. i.e.

$2[x^{2}-2(x)(2)+(2)^2-(2)^{2}]=5\\\\ 2[x^{2}-2(x)(2)+(2)^2]-2(2)^{2}=5\\\\ 2(x-2)^{2}-2(4)=5\\\\ 2(x-2)^2-8=5\\\\ 2(x-2)^{2}-8-5=0\\\\ 2(x-2)^{2}-13=0$

Comparing the above equation with the given equation:

$2(x-p)^{2}+q=0$ , we can say:

p = 2 and q= -13

6 0

3 years ago