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3 years ago

11

Find the measure of each angle please

1 answer:

Salsk061 [2.6K]3 years ago

8 0

B is 80
C and D are 50

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Using a sheet of graph paper, solve the following system of equations graphically. Be sure to show any work, use a straight edge

madam [21]

Answer:

<h2> (-1,1)</h2>

Step-by-step explanation:

Given system is

$\left \{ {{x+y=0} \atop {x-y+2=0}} \right.$

If we graph, the solution would be the interception point between these two lines, because each linear equation represents a line. The lines are attached.

In the graph, you can observe that the solution is the point (-1,1), that is x = -1 and y = 1.

Now, if we want to solve this system by another method, we can just sum both equations and solve for <em>x</em>

$\left \{ {{x+y=0} \atop {x-y+2=0}} \right.$

$2x+2=0\\x=\frac{-2}{2}=-1$

Then, we replace this value in one equation to find the other value

$x+y=0\\-1+y=0\\y=1$

Therefore, the solution is (-1,1)

4 0

3 years ago

Erica had 6 coins in her coin collection. she goes to a coin show and buys some coins. how many dose she have now?

rewona [7]

It doesnt say how many she buys at the coin show so we dont know but its going to be more than 6

8 0

3 years ago

Read 2 more answers

The leaning tower of Pisa currently "leans" at a 4 degree angle and has a vertical height of 55.86 meters. How tall was the lean

Marizza181 [45]

Answer:

56 meters.

Step-by-step explanation:

Please find the attachment.

Let the leaning tower's be h meters tall, when it was originally built.

We can see from our attachment that the side with length 55.86 meters is hypotenuse and h is adjacent side for 4 degree angle.

Since we know that cosine relates the adjacent and hypotenuse of a right triangle.

$\text{Cos}=\frac{\text{Adjacent}}{\text{Hypotenuse}}$

Upon substituting our given values we will get,

$\text{Cos (4)}=\frac{55.86}{h}$

$h=\frac{55.86}{\text{Cos (4)}}$

$h=\frac{55.86}{0.99756405026}$

$h=55.996\approx 56$

Therefore, the leaning tower was approximately 56 meters, when it was originally built.

6 0

3 years ago

Determine the sign of the leading coefficient

9966 [12]

Answer:

negative

Step-by-step explanation:

The graph falls to both the left and right, so the leading coefficient has to be negative, and it must be raised to an even power.

7 0

3 years ago

Oil is pumped continuously from a well at a rate proportional to the amount of oil left in the well. Initially there were millio

JulijaS [17]

Answer:

The amount of oil was decreasing at 69300 barrels, yearly

Step-by-step explanation:

Given

$Initial =1\ million$

$6\ years\ later = 500,000$

Required

At what rate did oil decrease when 600000 barrels remain

To do this, we make use of the following notations

t = Time

A = Amount left in the well

So:

$\frac{dA}{dt} = kA$

Where k represents the constant of proportionality

$\frac{dA}{dt} = kA$

Multiply both sides by dt/A

$\frac{dA}{dt} * \frac{dt}{A} = kA * \frac{dt}{A}$

$\frac{dA}{A} = k\ dt$

Integrate both sides

$\int\ {\frac{dA}{A} = \int\ {k\ dt}$

$ln\ A = kt + lnC$

Make A, the subject

$A = Ce^{kt}$

$t = 0\ when\ A =1\ million$ i.e. At initial

So, we have:

$A = Ce^{kt}$

$1000000 = Ce^{k*0}$

$1000000 = Ce^{0}$

$1000000 = C*1$

$1000000 = C$

$C =1000000$

Substitute $C =1000000$ in $A = Ce^{kt}$

$A = 1000000e^{kt}$

To solve for k;

$6\ years\ later = 500,000$

i.e.

$t = 6\ A = 500000$

So:

$500000= 1000000e^{k*6}$

Divide both sides by 1000000

$0.5= e^{k*6}$

Take natural logarithm (ln) of both sides

$ln(0.5) = ln(e^{k*6})$

$ln(0.5) = k*6$

Solve for k

$k = \frac{ln(0.5)}{6}$

$k = \frac{-0.693}{6}$

$k = -0.1155$

Recall that:

$\frac{dA}{dt} = kA$

Where

$\frac{dA}{dt}$ = Rate

So, when

$A = 600000$

The rate is:

$\frac{dA}{dt} = -0.1155 * 600000$

$\frac{dA}{dt} = -69300$

<em>Hence, the amount of oil was decreasing at 69300 barrels, yearly</em>

7 0

2 years ago