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tigry1 [53]
3 years ago
12

What is an equation of the line that passes through the points (6,8) and (-3,2)?

Mathematics
2 answers:
Elza [17]3 years ago
6 0
1. Use the slope formula
(6, 8) where x1 = 6 and y1 = 8
(-3, 2) where x2 = -3 and y2 = 2
Slope (m) = (y2-y1) / (x2-x1)
= (2-8) / (-3-6)
= -6 / -9
= 2/3

2. Use point-slope formula
y-y1=m(x-x1)
y-8=2/3(x-6)
y-8=2/3x -4

y = 2/3x + 4 :)
Orlov [11]3 years ago
4 0

Answer:

y=2/3x+4

Step-by-step explanation:

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wariber [46]

Answer:

a. 0.76

b. 0.23

c. 0.5

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f. 0.31

Step-by-step explanation:

a. p(AUBUC)= P(A)+P(B)+P(C)-P(AnB)-P(AnC)-P(BnC)+P(AnBnC)

                    =0.6+0.4+0.2-0.3-0.11-0.1+0.07= 0.76

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                    =0.3-0.07= 0.23

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e. P((AnB)/C))= P((AnB)nC)/P(C)

                     =P(AnBnC)/P(C)

                     =0.07/0.2= 0.35

f. P((AUB)/C)= P((AUB)nC)/P(C)

                    =(P(AnC) U P(BnC))/P(C)

                     =(0.11+0.1)/0.2

                     =0.21/0.2 = 0.31

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