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Anna [14]
3 years ago
5

What is the measure of x and y?

Mathematics
1 answer:
lisov135 [29]3 years ago
7 0

Answer:

x=80 and y=30

Step-by-step explanation:

HOPE THAT HELPS!!!!!!!

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10,9,8,7......
Charra [1.4K]

Answer:

30th term of the sequence is -19

Step-by-step explanation:

first term = 10

common difference = 9- 10 = -1

so, nth term = a + (n-1) d

( where n is number of term, a = first term ,

d = common difference. )

  • 30th term = 10 + (30-1) × -1
  • 30th term = 10 - 29
  • 30th term = -19

<em>i</em><em> </em><em>hope</em><em> </em><em>it</em><em> </em><em>helped</em><em>.</em><em>.</em><em>.</em>

3 0
3 years ago
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Find −2(− 4/7 ). You may find using a number line to be helpful. Enter your answer as a simplified mixed number.
elena55 [62]

Answer:

1.14285714

Step-by-step explanation:

6 0
3 years ago
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Which ordered pair is in the solution set of the system of inear inequaltes?
Galina-37 [17]
The answer is (2.2) so the other answer should be wrong
6 0
3 years ago
Omg, I'm so sorry people but it's a lot... -_-
Ne4ueva [31]

Answer:

this is Proportional

Step-by-step explanation:

0-0 there is nothing here

but 1-6 there's something

2-12 is when it become's proportional

1/6 = 2/12

5 0
3 years ago
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From 27 pieces of luggage, an airline luggage handler damages a random sample of four. The probability that exactly one of the d
dusya [7]

Answer:

0.273

Step-by-step explanation:

Let the number of insured pieces of luggage be <em>i</em> and <em>u</em> be the number of uninsured pieces of luggage, therefore,

<em>i </em>+ <em>u </em> = 27

Now,

probability that exactly one of the damaged pieces of luggage is insured = (iC1)(uC3)/(27C4)

probability that none of the damaged pieces are insured = (uC4)/(27C4)

and,

(iC1)(uC3)/(27C4) = 2 (uC4)/(27C4)

=> <em>u − </em>2<em>i </em>= 3

By solving, <em>i </em>+ <em>u </em> = 27 and  <em>u − </em>2<em>i </em>= 3

<em>i</em> = 8 and <em>u</em> = 19

and,

(8C2)(19C2)/(27C4) = 0.273

3 0
3 years ago
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