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iren2701 [21]
3 years ago
9

The pair of polygons is similar. find the value of x. answer on picture

Mathematics
2 answers:
tatyana61 [14]3 years ago
8 0
30\ in - 75\ in\\ 12\ in - x\ in\\ \\ 30x=75\cdot 12\\
30x=900\ /:30\\
x=30\ in
Y_Kistochka [10]3 years ago
6 0
30/75 = 12/x
30*x=75*12
30x=900/:30
x=30

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Can someone please help me solve this?
cestrela7 [59]

Answer:

(a)

Step-by-step explanation:

The tangent and the normal at point P are perpendicular.

Given

m_{tangent} = 3, then

Given the gradient m of the tangent then the gradient of a line perpendicular to it is

m_{normal} = - \frac{1}{m} = - \frac{1}{3} → (a)

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3 years ago
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PLZ HELP, DUE TONIGHT!! Find the values of a and b such that f(x) is continuous at x=1
Sedaia [141]

Answer:

  • a = 2, b = -4

Step-by-step explanation:

<u>To make the given piecewise function continuous we need:</u>

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<u>Sum of the two:</u>

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6 0
3 years ago
Find the equation of the line through point (8,−9) and perpendicular to 3+8=4.
raketka [301]

The equation of the line through the point (8,−9) and perpendicular to 3x+8y=4 is given by 8x - 3y = 91.

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y = mx + c,

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Also, two perpendicular lines' slopes are the negative reciprocals of one another.

Here, the equation of the given straight line is

3x+8y=4

i.e. 8y = 4 -3x

i.e. y = (4/8) - (3/8)x

Now the negative reciprocal of - 3/8 is 8/3.

Then we can write the equation of the perpendicular line is

y = (8/3)x + c ...(1)

Since (1) passes through the point (8, -9), so we can put x = 8 and y = -9 in (1) to get the value of c.

So, -9 = (8/3)*8 + c

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i.e. c = -9 -64/3 = - (27 + 64)/3 = - 91/3

(1) can be written as

y = (8/3)x - (91/3)

i.e. 3y = 8x - 91

i.e. 8x - 3y = 91

Therefore the equation of the line through the point (8,−9) and perpendicular to 3x+8y=4 is given by 8x - 3y = 91.

Learn more about perpendicular lines here -

brainly.com/question/12209021

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telo118 [61]

Answer:

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