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iren2701 [21]
3 years ago
9

The pair of polygons is similar. find the value of x. answer on picture

Mathematics
2 answers:
tatyana61 [14]3 years ago
8 0
30\ in - 75\ in\\ 12\ in - x\ in\\ \\ 30x=75\cdot 12\\
30x=900\ /:30\\
x=30\ in
Y_Kistochka [10]3 years ago
6 0
30/75 = 12/x
30*x=75*12
30x=900/:30
x=30

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The sale price of a router is 35% Off the regular price. The sale price is 117$. What was the regular price ?
sladkih [1.3K]

Okay, the equation would be: What is 35% of $117

Proportion:

\frac{x}{117} \frac{35}{100}

We multiply:

117 x 35 = 4095

Now we divide:

4095 / 100 = 40.95

Then we add:

40.95 + 117 = $157.95

and that's your answer!

I hope this helps! :)

7 0
3 years ago
Inez has to pay 4 percent in closing costs and 16 percent for the down payment on a purchase of $225,500 with an ARM. Over the l
Vinvika [58]
Answer for your question is (307,172.72)
6 0
3 years ago
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Write a decimal that is 1\10 of 0.9
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I am pretty sure it would be 0.09
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3 years ago
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A statement and portions of the flowchart proof are shown. Which reason should appear in box labeled 1?
larisa [96]

Answer:

Angle Addition Postulate

Step-by-step explanation:

Given:

m\angle UVW=30^{\circ}\\ \\m\angle WVX=75^{\circ}

Prove:

m\angle UVX=105^{\circ}

Proof:

1. m\angle UVX=m\angle UVW+m\angle WVX - Angle Addition Postulate

2. m\angle UVW=30^{\circ} - given

3. m\angle WVX=75^{\circ} - given

4. m\angle UVX=30^{\circ}+75^{\circ} - Substitution Property of Equality

5.  m\angle UVX=105^{\circ} - Simplify

4 0
4 years ago
A metalworker has a metal alloy that is 15​% copper and another alloy that is 75​% copper. How many kilograms of each alloy shou
lisov135 [29]

48 kilograms of 15 % copper is combined with 72 kilograms of 75 % copper to create 120 kg of a 51​% copper​ alloy

<em><u>Solution:</u></em>

Let "x" be the kilograms of 15 % copper

Then, (120 - x) be the kilograms of 75 % copper

Then, according to question,

"x" kilograms of 15 % copper is combined with (120 - x) kilograms of 75 % copper to create 120 kg of a 51​% copper​ alloy

Thus we frame a equation as:

15 % of x + 75 % of (120 - x) = 51 % of 120

<em><u>Solve the equation for "x"</u></em>

15 \% \times x + 75 \% \times (120-x) = 51 \% \times 120\\\\\frac{15}{100} \times x + \frac{75}{100} \times (120-x) = \frac{51}{100} \times 120\\\\0.15x + 0.75(120-x) = 0.51 \times 120\\\\0.15x + 90 - 0.75x = 61.2\\\\0.6x = 90 - 61.2\\\\0.6x = 28.8\\\\Divide\ both\ sides\ by\ 0.6\\\\x = 48

Thus 48 kilograms of 15 % copper used

Then, (120 - x) = (120 - 48) = 72

Thus, 72 kilograms of 75 % copper is used

4 0
3 years ago
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