1) The variables are "k"
2) There are 4 terms
3) The coefficients are k
4) The constants are -7, 3, 10, -5
5) The like terms is -7k, 3k, 10k, -5k
The answers are pretty direct but, hope this answers your question.
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Answer:
42 cm.
Step-by-step explanation:
Please find the attachment.
Let x be the length of diagonal of the square.
We have been given that length of each side of a square is 30 cm. We are asked to find the length of the diagonal of square to the nearest centimeter.
We can see from our diagram that triangle AC is the diagonal of our square.
Since all the interior angles of a square are right angles or equal to 90 degrees, so we will use Pythagoras theorem to find the length of diagonal.
Upon substituting our given values in above formula we will get,



Let us take square root of both sides of our equation.


Therefore, the length of diagonal of our given square is 42 cm.
Vbox-vspheres
vbox=, I assume we are dealing with l=w=h
so
v=lwh=12^3=1728
vsphere=(4/3)pir^3
r=3
vsphere=(4/3)pi3^3=4pi9=36pi
8 of them so
8 times 36pi=288pi or about 904.7786842338604526772412943845 cubic inches
vbox-sphere=1728-904.7786842338604526772412943845=823.2213157661395473227587056155
space filled by packing beads is about 823.22 cubic inches
beads percent is 823.2213157661395473227587056155/1728 times 100=47.64% filled by beads
I think it’s four. If not then I’m sorry
Yes it'll tessellate because if you notice the squares are only on the flat side of the hexagon and the triangles are on the corners