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Softa [21]
2 years ago
14

On a chilly day in New York, the temperature changed at -4 degrees per hour. How many hours did it take for the temperature to c

hange -36 degrees?
Mathematics
2 answers:
Aleks04 [339]2 years ago
6 0

Answer:

9 hours

Step-by-step explanation:

36 degrees total /4 degrees per hour = 9 hours

grigory [225]2 years ago
5 0
<h2>Required Answer:</h2>

\huge{\boxed{\sf{hours=9}}}

Question:

On a chilly day in New York, the temperature changed at -4 degrees per hour. How many hours did it take for the temperature to change -36 degrees?

<h2>Given:</h2>

  • Temperature changed in one hour = -4 degrees

<h2>To find :</h2>

  • hours did it take for the temperature to change -36 degrees
<h2 /><h2>Let </h2>
  • no. of hours =x
<h2>Answer:</h2>

Equation formed according to question:

→- 4 \times x =  - 36

→x =  \frac{ - 36}{ - 4}

→x = 9✓

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At a rugby match the ratio of children to adults is 2:3 .There are 80 children in the crowd .How many adults are in the crowd?​
NemiM [27]

Answer:

120

Step-by-step explanation:

80 represents the 2

Do 80 / 2 to get one 80 /2 = 40

So 1 would equal 40

Do 40 * 3 = 120 to get the three which represents the number of adults

7 0
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21 cm by 18cm by 15 cm what will the total sq cm
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5670 cm^{3} will be your answer!

Step-by-step explanation:

21 x 18 x 15 = 5670

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Is -9 a solution to 19&gt;8u+3
iVinArrow [24]
8u+3<19  subtract 3 from both sides

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4 0
2 years ago
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Solve the equation kx+9=7 for x
Alika [10]

Answer:

x=-2/k

Step-by-step explanation:

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First, you need to move the 9 to the other side by subtracting 9 from both sides: kx+9-9=7-9

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3 0
2 years ago
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ALGEBRAIC EXPRESSION 11. Subtract the sum of 13x – 4y + 7z and – 6z + 6x + 3y from the sum of 6x – 4y – 4z and 2x + 4y – 7. 12.
Naily [24]

Answer:

Explained below.

Step-by-step explanation:

(11)

Subtract the sum of (13x - 4y + 7z) and (- 6z + 6x + 3y) from the sum of (6x - 4y - 4z) and (2x + 4y - 7z).

[(6x - 4y - 4z) +(2x + 4y - 7z)]-[(13x - 4y + 7z) + (- 6z + 6x + 3y) ]\\=[6x-4y-4z+2x+4y-7z]-[13x-4y+7z-6z+6x+3y]\\=6x-4y-4z+2x+4y-7z-13x+4y-7z+6z-6x-3y\\=(6x+2x-13x-6x)+(4y-4y+4y-3y)-(4z+7z+7z-6z)\\=-11x+y-12z

Thus, the final expression is (-11x + y - 12z).

(12)

From the sum of (x² + 3y² - 6xy), (2x² - y² + 8xy), (y² + 8) and (x² - 3xy) subtract (-3x² + 4y² - xy + x - y + 3).

[(x^{2} + 3y^{2} - 6xy)+(2x^{2} - y^{2} + 8xy)+(y^{2} + 8)+(x^{2} - 3xy)] - [-3x^{2} + 4y^{2} - xy + x - y + 3]\\=[x^{2} + 3y^{2} - 6xy+2x^{2} - y^{2} + 8xy+y^{2} + 8+x^{2} - 3xy]- [-3x^{2} + 4y^{2} - xy + x - y + 3]\\=[4x^{2}+3y^{2}-xy+8]-[-3x^{2} + 4y^{2} - xy + x - y + 3]\\=4x^{2}+3y^{2}-xy+8+3x^{2}-4y^{2}+xy-x+y-3\\=7x^{2}-y^{2}-x+y+5

Thus, the final expression is (7x² - y² - x + y + 5).

(13)

What should be subtracted from (x² – xy + y² – x + y + 3) to obtain (-x²+ 3y²- 4xy + 1)?

A=(x^{2} - xy + y^{2} - x + y + 3) - (-x^{2}+ 3y^{2}- 4xy + 1)\\=x^{2} - xy + y^{2} - x + y + 3 +x^{2}- 3y^{2}+ 4xy -1\\=2x^{2}-2y^{2}+3xy-x+y+2

Thus, the expression is (2x² - 2y² + 3xy - x + y + 2).

(14)

What should be added to (xy – 3yz + 4zx) to get (4xy – 3zx + 4yz + 7)?

A=(4xy-3zx + 4yz + 7)-(xy - 3yz + 4zx) \\=4xy-3zx + 4yz + 7 -xy + 3yz - 4zx\\=3xy-7zx+7yz+7

Thus, the expression is (3xy - 7zx + 7yz + 7).

(15)

How much is (x² − 2xy + 3y²) less than (2x² − 3y² + xy)?

A=(2x^{2} - 3y^{2} + xy)-(x^{2} - 2xy + 3y^{2})\\=2x^{2} - 3y^{2} + xy-x^{2} + 2xy - 3y^{2}\\=x^{2}-6y^{2}+3xy

Thus, the expression is (x² - 6y² + 3xy).

7 0
3 years ago
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