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3 years ago

What is the y-intercept of the graph of y = 5x – 2?

Mathematics

1 answer:

MakcuM [25]3 years ago

4 0

The y intercept is -2 :)

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How do you solve this linear equation 3x+2=x+2x+4 ?

Svetach [21]

3x+2=x+2x+4
-2 -2
3x=x+2x+4-2
3x=3x+4-2
-3x -3x
x= 4-2
x=2

7 0

3 years ago

Read 2 more answers

Identify the vertex of the parabola.

7nadin3 [17]

I think is c be cause I took test

5 0

3 years ago

Read 2 more answers

PLSS HELP

Dmitry [639]

Answer:

$8,000

Step-by-step explanation:

Let the store earned $x in December.

Therefore,

Money spent to buy new inventory $=\frac{1}{4} x$

Remaining money $= x - \frac{1}{4} x =\frac{3}{4} x$

Money used to pay bills $=\frac{1}{2} \times \frac{3}{4} x=\frac{3}{8} x$

Money still left over = $3,000

Total money earned in December $= \frac{1}{4} x+ \frac{3}{8} x+3,000$

$\therefore x= \frac{1}{4} x+ \frac{3}{8} x+3,000$

$\therefore x= \frac{2}{8} x+ \frac{3}{8} x+3,000$

$\therefore x= \frac{5}{8} x+ 3,000$

$\therefore x- \frac{5}{8} x=3,000$

$\therefore \frac{8x-5x}{8} =3,000$

$\therefore \frac{3x}{8} =3,000$

$\therefore x =3,000\times \frac {8}{3}$

$\therefore x =1,000\times 8$

$\therefore x =\$8,000$

Thus, total money earned in December is $8,000.

3 0

3 years ago

Negative three times a number is at least 57.

castortr0y [4]

The option formatting isn't very clear, anyway: given a number x, negative 3 times that number is -3x. If this has to be at least 57, it means that -3x must be greater than or equal to 57:

$-3x\geq 57$

Dividing both sides by -3 solves the equation, but we have to switch the inequality sign because we're dividing by a negative number:

$x\leq \dfrac{57}{3}=19$

4 0

3 years ago

Suppose a quiz has 12 multiple choice questions. Each question has 4 answer choices. If a student takes the quiz and randomly gu

Gnoma [55]

The probability that the student gets between 1 and 6, exclusive, questions correct will be 0.7872...

Explanation

If the probability of success is $p$ , then the probability of $r$ successes in $n$ trials will be......

$P = ^nC_{r}*(p)^r (1-p)^n^-^r$

Here, the quiz has total 12 questions and each question has 4 answer choices. So, $n=12$ and $p=\frac{1}{4}= 0.25$

The student gets between 1 and 6, exclusive, questions correct. It means there can be 2 or 3 or 4 or 5 questions as correct. So....

The probability of 2 or 3 or 4 or 5 questions correct will be:

$=^1^2C_{2}*(0.25)^2(1-0.25)^1^0 + ^1^2C_{3}*(0.25)^3(1-0.25)^9 +^1^2C_{4}*(0.25)^4(1-0.25)^8+^1^2C_{5}*(0.25)^5(1-0.25)^7\\ \\ =0.2322...+0.2581...+0.1935...+0.1032... \\ \\ =0.7872...$

3 0

3 years ago