In order to solve for parallel, perpendicular, or neither, you have to look at the slope.
If the slope is the same for both equations, it is most likely parallel.
If it's the reciprocal (Where you flip the number and add change the signs. For example, the reciprocal of 1/2 is -2)
If the slope is not the same or the reciprocal, then it is neither.
So for the first equation, your slope is:
3x+2y=6
2y=-3x+6
y=-3/2x+3 The equation y=mx+b can help you here, where m is the slope.
Your slope is -3/2
For the second equation, your slope is -3/2 since y=-3/2x+5 is already in y=mx+b form and m is the slope.
Since both slopes are -3/2, then you have parallel equations!
(Be careful though, sometimes it will have the same slope but there will also be the same y-intercept. If that happens, it's no longer parallel, but it's the same equation. Such as y=-3/2x+1 and y=-3/2x+1. In this case there will be infinite solutions, but parallel equations have no solutions.)
I hope this helps!! Please ask if you have more questions!
Answer:
A
Step-by-step explanation:
You have to plug numbers into point slope formula (make sure to use a slope of -4/3 since its perpendicular) and then solve for y.
Consecutive integers mean one after the other and their difference would one more or less.
Let the numbers be x, x +1, x +2.
Therefore x + (x+1) + (x +2) = 567
3x + 3 = 567
3x = 567 -3 = 564
3x = 564 Divide by 3.
x = 564/3
x = 188
Therefore integers x, x +1, x +2 = 188, 188+1, 188+2.
= 188, 189, 190.
Cheers.
0= -3x+9
-9=-3x
3=x
Final answer: x=3
There is only one zero because it is linear, and can therefore only cross the x axis once.
