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DIA [1.3K]
3 years ago
10

Tanya is 42 years old. she would like to open aretirement account so she will have half a million dollars in the account when sh

e retires at the age 65. how much did she deposit each month into an account with an apr of 2.75% to reach her goal?
Mathematics
1 answer:
gladu [14]3 years ago
7 0
Let the total amount that Sarah deposited be $x
using the annuity formula:
A=P[((1+r)^n-1)/r]
A=future value
r=rate
n=number of years
from the information given:
A=$500000
r=2.75%
n=65-42=23 years
p=$x
thus plugging our values in the formula we get:
500000=x[((1+0.0275)^(23)-1)/(0.0275)]
500000=31.50x
x=15,872.04883
She deposited 15,873.04883 per year
The monthly deposit will therefore be:
15873.04883/12=$1322.67
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27 km<br> 36 km<br> What is the length of the hypotenuse?
just olya [345]

Answer:

The length of hypotenuse is 45 kilometers

Step-by-step explanation:

Assuming that given lengths are of perpendicular and hypotenuse, and the triangle is a right angled triangle

Perpendicular = P = 27 km

Base = B = 36 km

Hypotenuse = H = ?

We can use Pythagoras theorem for finding the length of hypotenuse

The Pythagoras theorem is given by:

H^2 = B^2+P^2

Putting the values, we get

H^2 = (36)^2 + (27)^2\\H^2 = 1296 + 729\\H^2 =2025

Taking square root on both sides

\sqrt{H^2} =\sqrt{2025}\\H =45

Hence,

The length of hypotenuse is 45 kilometers

4 0
3 years ago
Find the distance between the two points: (3,-2) and (14. -8). State your answer as a radical square root) if necessary to be ex
djyliett [7]

Answer:

\sqrt{157} units  

Step-by-step explanation:

Use the distance formula d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\ to find the distance between the two points. Substitute the x and y values of (3, -2) and (14, -8) into the formula and simplify like so:

d = \sqrt{(14-3)^2+(-8-(-2))^2} \\d = \sqrt{(11)^2+(-8+2)^2} \\d = \sqrt{121+(-6)^2} \\d =\sqrt{121+36} \\d=\sqrt{157}

So, the distance is \sqrt{157} units.

7 0
3 years ago
Solve the equation below by completing the square and then solving for x. X2 - 6x + 1 = 17
blsea [12.9K]

The expression for the square of a binomial is

(a+b)^2 = a^2+2ab+b^2

Since your expression starts with x^2-6x +\ldots

It means that a = x, and so -6x must be twice the product of x and some number b. If you choose b = -3 you have

(x-3)^2 = x^2-6x+9

So, if you add 8 to both sides of your equation, you have

x^2-6x+1+8 = 17+8 \iff x^2-6x+9 = 25 \iff (x-3)^2=25 \iff x-3 = \pm 5

By choosing one sign at a time, we have the two solutions

x_1 \to x-3 = 5 \iff x = 8

x_2 \to x-3 = -5 \iff x = -2

7 0
3 years ago
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