Answer:
Step-by-step explanation:
Let's graph both functions
The solutions are the coordinates of the intersection point
The intersection point is (-7,5)
So
● x = -7
● y = 5
Equation 2 is a square root function, kind of like half of a sideways parabola, Equation 3 is a parabola, and 4 is a cubic function (s-shaped). This leaves Equation 1, which is a line with a slope of 2 with a y-intercept at 7. So I'd say the answer is 1.
Answer:
The correct option is A.
Step-by-step explanation:
Domain:
The expression in the denominator is x^2-2x-3
x² - 2x-3 ≠0
-3 = +1 -4
(x²-2x+1)-4 ≠0
(x²-2x+1)=(x-1)²
(x-1)² - (2)² ≠0
∴a²-b² =(a-b)(a+b)
(x-1-2)(x-1+2) ≠0
(x-3)(x+1) ≠0
x≠3 for all x≠ -1
So there is a hole at x=3 and an asymptote at x= -1, so Option B is wrong
Asymptote:
x-3/x^2-2x-3
We know that denominator is equal to (x-3)(x+1)
x-3/(x-3)(x+1)
x-3 will be cancelled out by x-3
1/x+1
We have asymptote at x=-1 and hole at x=3, therefore the correct option is A....
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Step-by-step explanation: Idk how to explain I’m just smart so I can figure it out
I think it would be 2 days. you would get it done 4 times faster, so 8/4 is 2
