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Ivenika [448]
4 years ago
8

How do graphs and equations reveal information about a relationship between two quantities

Mathematics
2 answers:
ohaa [14]4 years ago
7 0
When two quantities have a relationship, there is a corresponding equation that could describe it. These two quantities may be expressed in variables of x and y. When you plot the graph, you may see a line or a curve. This presents the trend of the relationship of the two quantities when the independent variable changes.
grin007 [14]4 years ago
5 0

Answer with explanation:

→→→The relationship between two Quantities can be expressed in either linear form which means Direct relationship or inverse relationship.

This can be expressed in the following way:

 →  y=a x +b------(1)

or

\rightarrow y=\frac{k}{x}

                                       --------------------------(2)

→You can take any of the variable as Independent Variable and another as Dependent Variable.

→→→Equation (1) shows direct relationship between  two variables whereas equation (2) shows inverse relationship between two variables.

When you represent this in graphical form one will be Linear and other will be in the shape of Rectangular Hyperbola.

For example:

→ y=2 x +3

And→→, \rightarrow y=\frac{2}{x}

Can be represented graphically as follows.

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Round each number to the place of the underlined digit 32.65
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3 years ago
A recent study by Ohio State University reported at Science Daily suggests that students with cell phones may take more risks th
777dan777 [17]

Answer:

The value of the test statistic z for this hypothesis test is -2.79

Step-by-step explanation:

Consider the provided information.

To calculate the test statistic use the formula:

z=\frac{\hat p-p_0}{\sqrt{\frac{p_0(1-p_0)}{n}}}

Where, z  is Test statistics, n is Sample size, p₀ = Null hypothesized value  and \hat p = Observed proportion.

p₀ = 0.50

Thus 1-p₀= 0.50

42% responded that if they had a cell phone, thus \hat p=0.42

The sample size is 305.

Substitute the respective values in the above formula.

z=\frac{0.42-0.50}{\sqrt{\frac{0.50(0.50)}{305}}}

z=\frac{-0.08}{\sqrt{0.00082}}

z=-2.79

Hence, the value of the test statistic z for this hypothesis test is -2.79

4 0
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nasty-shy [4]

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Step-by-step explanation:

4 0
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Data Entry - No Scoring During your procedure to determine the uncalibrated volume near the stopcock of your buret, what was the
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Answer:

0.025 grams

Step-by-step explanation:

The water in the stopcock has a volume of 25 mL initially, After that, the whole water was drained out. So we have:

Volume of drained water = (25 mL)(1 x 10⁻⁶ m³/1 mL)

Volume of drained water = 25 x 10⁻⁶ m³

Density of drained water = 1000 kg/m³

So, for the mass of drained water:

Density of drained water = Mass of drained water/Volume of drained water

Mass of drained water = (Density of drained water)(Volume of drained water)

Mass of drained water = (1000 kg/m³)(25 x 10⁻⁶ m³)

<u>Mass of drained water = 0.025 gram</u>

Density

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What is the rate of change of y=-3x - 2​
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Answer:

-3

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The rate of change is equal to the slope. In this slope intercept form (y=mx+b) m is the slope. Therefore m=-3 and that is the rate of change.

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4 years ago
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