1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lidiya [134]
3 years ago
11

Kent worked in the houseware section of a department store. This year he set a record high for vacuum sales with567 vacuum sold.

The previous yearhigh was set last year, when 540 vacuums were sold. What is the percent of increase in sales from last year to this year?
Mathematics
1 answer:
Gemiola [76]3 years ago
5 0
First subtract the original high from the new high:
567 - 540 = 27 more vacuums sold.

Now divide the increase amount by the original high and multiply that by 100 to get the percentage:

27 / 540 = 0.05

0.05 * 100 = 5% Increase.
You might be interested in
Write a story problem that involves fractions with unlike denominators. Include the solution.
Lady_Fox [76]
<span>a horse ran 7/8 of a mile and trots 2/4 of a mile. How much farther did the horse run than trot? 

Best of luck!!!☺

PS if you need the answer just tell me i will tell you :)</span>
3 0
3 years ago
Read 2 more answers
A country has 32 parks that allow camping and 43 parks that have playgrounds. Of those, 10 parks both allow camping and have pla
Olenka [21]

Answer:

25

Step-by-step explanation:

Given:

32 parks allow camping

43 parks allow playgrounds

10 parks both allow camping and playgrounds

110 total parks

First, we need to add 32, 43, and 10

32 + 43 + 10 = 85

Then, we find the difference of 110 and 85

110 - 85 = 25

Since it isn't a decimal, there is no point in rounding.

8 0
4 years ago
That you're positive that you should be trying out these difficult math questions, let’s get right to it! The answers to these q
Lemur [1.5K]

Answer:

that you're positive that you should be trying out these difficult math questions, let’s get right to it! The answers to these questions are in a separate section below, so you can go through them all at once without getting spoiled.

#1:

body_ACT_0506_-_56

#2:

body_ACT_0506_-_59

#3:

body_ACT_0809_-_38_J

#4:

body_ACT_0809_-_54

#5:

body_ACT_0809_-_55-1

#6:

body_ACT_0809_-_56

#7:

body_ACT_0809_-_57-1

#8:

body_ACT_0809_-_60

#9:

body_ACT_1112_-__48-1

#10:

body_ACT_1112_-_45

#11:

body_ACT_1112_-_51-1

#12:

body_ACT_1112_-_52

#13:

body_ACT_1112_-_53

#14:

body_ACT_1112_-_58

#15:

body_ACT_1314_-_55-1

Step-by-step explanation:

5 0
3 years ago
Binomial Expansion/Pascal's triangle. Please help with all of number 5.
Mandarinka [93]
\begin{matrix}1\\1&1\\1&2&1\\1&3&3&1\\1&4&6&4&1\end{bmatrix}

The rows add up to 1,2,4,8,16, respectively. (Notice they're all powers of 2)

The sum of the numbers in row n is 2^{n-1}.

The last problem can be solved with the binomial theorem, but I'll assume you don't take that for granted. You can prove this claim by induction. When n=1,

(1+x)^1=1+x=\dbinom10+\dbinom11x

so the base case holds. Assume the claim holds for n=k, so that

(1+x)^k=\dbinom k0+\dbinom k1x+\cdots+\dbinom k{k-1}x^{k-1}+\dbinom kkx^k

Use this to show that it holds for n=k+1.

(1+x)^{k+1}=(1+x)(1+x)^k
(1+x)^{k+1}=(1+x)\left(\dbinom k0+\dbinom k1x+\cdots+\dbinom k{k-1}x^{k-1}+\dbinom kkx^k\right)
(1+x)^{k+1}=1+\left(\dbinom k0+\dbinom k1\right)x+\left(\dbinom k1+\dbinom k2\right)x^2+\cdots+\left(\dbinom k{k-2}+\dbinom k{k-1}\right)x^{k-1}+\left(\dbinom k{k-1}+\dbinom kk\right)x^k+x^{k+1}

Notice that

\dbinom k\ell+\dbinom k{\ell+1}=\dfrac{k!}{\ell!(k-\ell)!}+\dfrac{k!}{(\ell+1)!(k-\ell-1)!}
\dbinom k\ell+\dbinom k{\ell+1}=\dfrac{k!(\ell+1)}{(\ell+1)!(k-\ell)!}+\dfrac{k!(k-\ell)}{(\ell+1)!(k-\ell)!}
\dbinom k\ell+\dbinom k{\ell+1}=\dfrac{k!(\ell+1)+k!(k-\ell)}{(\ell+1)!(k-\ell)!}
\dbinom k\ell+\dbinom k{\ell+1}=\dfrac{k!(k+1)}{(\ell+1)!(k-\ell)!}
\dbinom k\ell+\dbinom k{\ell+1}=\dfrac{(k+1)!}{(\ell+1)!((k+1)-(\ell+1))!}
\dbinom k\ell+\dbinom k{\ell+1}=\dbinom{k+1}{\ell+1}

So you can write the expansion for n=k+1 as

(1+x)^{k+1}=1+\dbinom{k+1}1x+\dbinom{k+1}2x^2+\cdots+\dbinom{k+1}{k-1}x^{k-1}+\dbinom{k+1}kx^k+x^{k+1}

and since \dbinom{k+1}0=\dbinom{k+1}{k+1}=1, you have

(1+x)^{k+1}=\dbinom{k+1}0+\dbinom{k+1}1x+\cdots+\dbinom{k+1}kx^k+\dbinom{k+1}{k+1}x^{k+1}

and so the claim holds for n=k+1, thus proving the claim overall that

(1+x)^n=\dbinom n0+\dbinom n1x+\cdots+\dbinom n{n-1}x^{n-1}+\dbinom nnx^n

Setting x=1 gives

(1+1)^n=\dbinom n0+\dbinom n1+\cdots+\dbinom n{n-1}+\dbinom nn=2^n

which agrees with the result obtained for part (c).
4 0
3 years ago
The Polygons are similar. Find the value of x. ​
ollegr [7]

Answer:

13

Step-by-step explanation:

8/2=16/4

=4

x-3=2.5*4

x=10+3

x=13

8 0
3 years ago
Read 2 more answers
Other questions:
  • The dimensions of a rectangular garden were 4m by 5m. each dimension was increased b the same amount. the garden then had an are
    12·1 answer
  • Need some help with these last few problems Thank you for your time and help
    6·1 answer
  • Antar is flying a triangular-shaped kite. it has a height of 4 1/2 feet and a base of 5 3/4 feet. what is the area of Antar's ki
    11·1 answer
  • Five to the second power +10.2 times 4-2
    7·2 answers
  • WILL MARK BRAINLIEST!!!
    10·1 answer
  • Solve for x. y = x + 6
    15·2 answers
  • What is the surface area of the regular pyramid below? I’ll would be helpful if you guys list down the steps !
    10·1 answer
  • jamie has 8/10 of a candy bar leftover. He wants to spilt it into 1/3 pieces . How many 1/3 pieces can he make
    5·1 answer
  • Basic Computation: Finding Probabilities, let z be a random variable with a standard normal distribution. Find the indicated pro
    14·1 answer
  • Plzzz help I’m being timed!!!
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!