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hoa [83]
3 years ago
8

Which situation is modeled by the graph?

Mathematics
2 answers:
Debora [2.8K]3 years ago
5 0

Answer:

A. The height of a jump rope being used over time

Step-by-step explanation:

We have, the height is related periodically to the time.

<em>That is, as the time increases the height increases and decreases in a periodic manner.</em>

So, from the options, we see that,

B. The height of an elevator over time.

If we assume any line parallel to x-axis as the ground, then the elevator's height also have negative values.

Thus, this option is discarded.

C. The height of a commuter airplane over time.

The commuter plane once in the air, flies at a constant speed.

That is, the height graph will be parallel to the x-axis in this case.

So, this option is discarded.

D. The height of a hummingbird at a feeder.

The height of a humming bird varies randomly with respect to time and cannot be represented by a periodic function.

So, this option is also discarded.

But, the movement of jump rope is periodic and can be represented by a periodic function as shown.

Hence, option A is correct.

ohaa [14]3 years ago
3 0
Well i know by looking for sure it is not D or C. so that eliminates 2 answers which leaves A and B. i believe the best answer for this is A. if i am wrong please let me know, if i am correct then let me know swell. hope this helps.
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HELP MEE!!!
SIZIF [17.4K]

A- none because they are parallel lines

5 0
4 years ago
A compressed air tank carried by scuba divers has a volume of 8.00 L and a pressure of 141 atm at 22.0°C. What is the volume (in
weqwewe [10]

Answer:

Volume of air in the tank =1,044 Liter

Step-by-step explanation:

Given:

Tank volume = 8 Liter

Pressure = 141 atm

Temperature = 22°C = 273° + 20° = 295° K

Find:

Volume of air in the tank = ?

Computation:

\frac{Pressure\times Tank\ volume}{Tempreture} =\frac{Pressure\times Air\ volume}{Tempreture}\\\\\frac{141\times 8}{295} =\frac{1\times Air\ volume}{273.15}\\\\\frac{1,128}{295} =\frac{Air\ volume}{273.15}\\\\Air\ volume=1,044.45

Volume of air in the tank =1,044 Liter

8 0
3 years ago
A rectangle ahs a long side of a length 8.5 cm its perimeter is 24cm work out the length of the shorter side
Phantasy [73]

Answer:

Width (length of shorter side) = 3.5 cm.

Step-by-step explanation:

L = 8.5 cm

perimeter, P = 24 cm

2(L+W) = 24

substitute L = 8.5

2(8.5+W) = 24

8.5 + W = 24/2 = 12

W = 12 - 8.5 = 3.5 cm

5 0
3 years ago
Two mathematical questions attached below.
BartSMP [9]

Answer:

See below

Step-by-step explanation:

9.( {m}^{3}  {n}^{5} )^{ \frac{1}{4} }   \\   =  m^{\frac{3}{4}}n^{\frac{5}{4}}\\  \\ 10. \sqrt[5]{ \sqrt[4]{x} }  \\  =  \sqrt[5]{ {x}^{ \frac{1}{4} } }  \\  =  {( {x}^{ \frac{1}{4} } )}^{ \frac{1}{5} }  \\   =  {x}^{ \frac{1}{4}  \times  \frac{1}{5} }  \\  =  {x}^{ \frac{1}{20} }  \\  \\ \sqrt[5]{ \sqrt[3]{ {a}^{2} } }  \\  =  \sqrt[5]{ {a}^{ \frac{2}{3} } }  \\  =  {( {a}^{ \frac{2}{3} } )}^{ \frac{1}{5} }  \\   =  {a}^{ \frac{2}{3}  \times  \frac{1}{5} }  \\  =  {a}^{ \frac{2}{15} }

4 0
3 years ago
For the class of 2013's prom Norman's dress shop sold cheaper dresses for $90 each and more expensive dresses for $140 each. The
Tema [17]

Answer:

Number of cheaper dresses sold  is 35

Number of expensive  dresses sold  is 15

Step-by-step explanation:

Given:

Cost of cheaper dresses = $90

Cost of  expensive dresses = $140

Total cost of  the dresses = $5250

To Find:

Number of cheaper dress = ?

Number of expensive  dress = ?

Solution:

Let

The number of  cheaper dresses be x

The number of  expensive dresses be y

(Number of cheaper dresses X cost of cheap dress) +  (Number of Expensive dresses X cost of  expensive dress)  =  $5250

x \times90 +y \times 140 = 5250=  $5250

It is given that the 20 more of the cheaper dresses than the expensive dresses is sold

So,

number of cheaper dress  =  20  +  number of expensive dress

x = 20 + y---------------------------------------(1)

(20+y) \times90 +y \times 140 = 5250 = 5250

(20 \times 90 +y\times 90) +y \times 140= 5250

1800 + 90y+ 140y = 5250

1800 + 230y = 5250

230y =5250 -1800

230y = 3450

y = \frac{3450}{230}

y = 15

Substituting y in (1)

x = 20 +15

x= 35

5 0
4 years ago
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