Answer:
![(x-5)^{2}](https://tex.z-dn.net/?f=%28x-5%29%5E%7B2%7D)
Step-by-step explanation:
![ax^{2} + bx + c](https://tex.z-dn.net/?f=ax%5E%7B2%7D%20%2B%20bx%20%2B%20c)
Take the value for b, divide it by 2 and square it to get the value for c.
In this case, b = -10.
- 10 ÷ 2 = -5
-5^2 = 25
So x^2 - 10x +25 is your quadratic equation which is equal to
![(x-5)^{2}](https://tex.z-dn.net/?f=%28x-5%29%5E%7B2%7D)
First, change the mixed fraction into improper fraction
1 1/7 = 7/7 + 1/7 = 8/7
(4/7)/(8/7)
To solve, flip the second fraction, and change the division into multiplication
(4/7)/(8/7) = (4/7) x (7/8)
Multiply, and simplify
(4/7) x (7/8) = 28/56, or 1/2
1/2 is your answer
hope this helps
Midpoint of EF = ((-2 + 1)/2, (3 + 6)/2) = (-1/2, 9/2)