Answer:
(a) 
(b)300 Hours
(c)150 Hours
(d)Reduced and halved.
(e) 
Step-by-step explanation:
(a) The number of hours worked is inversely proportional to the wage.
This is written as:
(b)If the student earns $8 an hour
w=$8
(c)When the wage per hour =$16
When w=$16
The number of hours reduced and is in fact halved.
(d)
The effect of raising the wage from $w to $2w per hour is that the number of hours required to work is reduced and exactly halved.
(e)The wage per hour is inversely proportional to the number of hours.
In fact,
Answer:
Its D
Step-by-step explanation:
x = 1
x = -1
x= 0.0000 - 3.0000 i
x= 0.0000 + 3.0000 i
Reformatting the input :
Changes made to your input should not affect the solution:
(1): "x2" was replaced by "x^2". 4 more similar replacement(s).
Step by step solution :
Step 1 :
Equation at the end of step 1 :
((((((x6)-(2•(x5)))+(9•(x4)))-24x3)-x2)+18x)-9 = 0
Step 2 :
Equation at the end of step 2 :
(x6)-(2•(x5)+(32x4)-24x3)-x2)+18x)-9 = 0
Step 3 :
Equation at the end of step 3 :
(x6)-2x5)+32x4)-24x3)-x2)+18x)-9 = 0
Answer:
2a could be combined with 5a
Step-by-step explanation:
they both have an (a) after them
Answer: 9
Step-by-step explanation:
NOT NECESSARILY would a triangle be equilateral if one of its angles is 60 degrees. To be an equilateral triangle (a triangle in which all 3 sides have the same length), all 3 angles of the triangle would have to be 60°-angles; however, the triangle could be a 30°-60°-90° right triangle in which the side opposite the 30 degree angle is one-half as long as the hypotenuse, and the length of the side opposite the 60 degree angle is √3/2 as long as the hypotenuse. Another of possibly many examples would be a triangle with angles of 60°, 40°, and 80° which has opposite sides of lengths 2, 1.4845 (rounded to 4 decimal places), and 2.2743 (rounded to 4 decimal places), respectively, the last two of which were determined by using the Law of Sines: "In any triangle ABC, having sides of length a, b, and c, the following relationships are true: a/sin A = b/sin B = c/sin C."¹
