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3 years ago

15

Keith mows lawns in his neighborhood. He charges a base rate of $15 per lawn and then charges $5 per hour, h, it takes him to mo

w the lawn. Keith wants to make more than $100 today. Which inequality below represents the situation?

1 answer:

Bogdan [553]3 years ago

7 0

Answer:

y * ((h * x) + 15)

Step-by-step explanation:

l (Lawns)

h = hours

x = number of hours

y = number of lawns

y * ((h * x) + 15)

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Order -6.6,5.8,-6 3/4,27/5,-5 5/8 from least to greatest

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Which transmition will change figure A into figure B in math

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Answer:

The figures informed are in different scales and mirrored in this way it will be necessary to rotate 180 about the origin, dilate by a scale factor of 2/3.

Step-by-step explanation:

What is figure rotation?

Rotation is the "turn" of a shape around a point called the center of rotation. The distance to the center of rotation remains constant and the measure of rotation is called the angle of rotation.

In this case, first the figure must be rotated 180 degrees since the images are mirrored and then change the scale so that a dilation of 2/3 occurs.

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1 year ago

Consider a normal distribution curve where the middle 85 % of the area under the curve lies above the interval ( 8 , 14 ). Use t

NeTakaya

Answer:

$\mu = 11$

$\sigma = 2.08$

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Middle 85%.

Values of X when Z has a pvalue of 0.5 - 0.85/2 = 0.075 to 0.5 + 0.85/2 = 0.925

Above the interval (8,14)

This means that when Z has a pvalue of 0.075, X = 8. So when $Z = -1.44, X = 8$ . So

$Z = \frac{X - \mu}{\sigma}$

$-1.44 = \frac{8 - \mu}{\sigma}$

$8 - \mu = -1.44\sigma$

$\mu = 8 + 1.44\sigma$

Also, when X = 14, Z has a pvalue of 0.925, so when $X = 8, Z = 1.44$

$Z = \frac{X - \mu}{\sigma}$

$1.44 = \frac{14 - \mu}{\sigma}$

$14 - \mu = 1.44\sigma$

$1.44\sigma = 14 - \mu$

Replacing in the first equation

$\mu = 8 + 1.44\sigma$

$\mu = 8 + 14 - \mu$

$2\mu = 22$

$\mu = \frac{22}{2}$

$\mu = 11$

Standard deviation:

$1.44\sigma = 14 - \mu$

$1.44\sigma = 14 - 11$

$\sigma = \frac{3}{1.44}$

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