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3 years ago

Tìm nghiện của đa thức A.x-2 B.2x-7 C.(X-4)*(2-3X

Mathematics

1 answer:

Vitek1552 [10]3 years ago

6 0

Answer:

make me brainlest if you copy okay

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In a triangle ABC, with angles A, B, and C and sides AB, BC, and AC, angle B is a right (90°) angle. If the sin of angle A is 0.

rewona [7]

I hope this helps you

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4 years ago

2.) Fill in the blank.

Montano1993 [528]

Answer:

E.) 1

Step-by-step explanation:

Firstly we will solve for L.H.S.

L.H.S. = $Csc^2\theta$

Since we know that $Csc^2\theta$ is the inverse of $Sin^2\theta$ .

So we can say that;

$csc^2\theta=\frac{1}{sin^2\theta}$

Now For R.H.S.

$Cot^2\theta+1$

Since we can rewrite $cot^2\theta$ as $\frac{cos^2\theta}{sin^2\theta}$ .

Now we can say that the R.H.S. is;

$\frac{cos^2\theta}{sin^2\theta}+1$

Now we add the fraction and get;

$\frac{cos^2\theta+sin^2\theta}{sin^2\theta}$

Now according to trigonometric identity;

$cos^2\theta+sin^2\theta=1$

So, $\frac{cos^2\theta+sin^2\theta}{sin^2\theta}=\frac{1}{sin^2\theta}$

Here,

$csc^2\theta=\frac{1}{sin^2\theta}$ and $Cot^2\theta+1$ = $\frac{1}{sin^2\theta}$ <em> </em>

L.H.S. = R.H.S.

Hence $csc^2\theta=cot^2\theta+1$

4 0

3 years ago

The track team is trying to reduce their time for a relay race. First they reduce their time by 2.1 minutes. Then they are able

klemol [59]

Answer: 15.7 minutes

Step-by-step explanation:

Let x be the time in the beginning (in minutes).

Given: The track team is trying to reduce their time for a relay race.

First they reduce their time by 2.1 minutes.

Then they are able to reduce that time by 10

If their final time is 3.96 minutes, then

x-t1-t2= 3.6
x= 3.6+ t1+ t2
x= 3.6+ 2.1+ 10
x= 15.7

Hence, their beginning time was 15.7 minutes.

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3 years ago

Can someone help me with this

jarptica [38.1K]

The answer is y=- 7/6x+8
Plz mark me Brainly

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3 years ago

a cube of wood exerts a pressure of 2Pa when it is placed on a floor . What is the force exerted by the cube if its surface area

svlad2 [7]

Duh it’s 5m square that’s the angels

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3 years ago