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seraphim [82]
3 years ago
6

I need to know the distance and if your could please tell me the formula for future problems thank you!! ASAP

Mathematics
1 answer:
Ksivusya [100]3 years ago
8 0

Distances in 2- and 3-dimensions (and even higher dimensions) can be found using the Pythagorean theorem. The straight-line distance can be considered to be the hypotenuse of a right triangle whose sides are the horizontal and vertical differences between the coordinates.

Here, you have A = (0, 0) and B = (3, 6). The horizontal distance between the points is ...

... 3 - 0 = 3 . . . . the difference of x-coordinates

The vertical distance between the points is ...

... 6 - 0 = 6 . . . . the difference of y-coordinates

Then the straight-line distance (d) between the points is found from the Pythagorean theorem, which tells you ...

... d² = 3² + 6²

... d = √(9 + 36) = √45 ≈ 6.7 . . . units

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Anderson has been saving his earnings from mowing the neighborhood lawns. he has 70 dollars and wants to spend it all on movies.
frutty [35]
70 = 4x
x equals the number of movies 

divide both sides by 4

70 / 4 = x
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Anderson will be able to go to 17 movies
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Frank deposited $100 into an account that earns 4% interest which is compounded 4 times per year. How much money will Frank have
Simora [160]
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3 years ago
Find the LCD of the fractions, and then simplify the expression. Assume that no denominator equals zero. 5/(3x^2y) - 4/(6xy^3
tamaranim1 [39]
The LCD = 6x^2y^3    ( because LCD of 3 and 6 = 6,  LCD of x^2 and x = x^2 and LCD of y and y^3 = y^3)

now divide 3x^2y into the LCD  then multiply this  by 5 to get the first term in the numerator  and do similar process to get second term, so we get:-

5(2y^2) - 4(x)
------------------
   6x^2y^3

=  2( 5y^2 - 2x)
   -----------------
        6x^2y^3

=    5y^2 - 2x
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5 0
4 years ago
Julian walked 6/10 of a mile to his friends house and another 35/100 mile to the store. He walked 1/4 of a mile back home. Julia
AveGali [126]

The statement, "Julian's sister said he walked 1/5 mile" cannot be agreed because Julian totally walked 1\frac{1}{5} \text{ or } \frac{6}{5} miles.

<u>Solution:</u>  

Given that,

  • Julian walked 6/10 of a mile to his friends house
  • Another 35/100 mile to the store
  • He walked 1/4 of a mile back home

To find total distance walked by Julian we have to add the above stated values. That is, \frac{6}{10} +\frac{35}{100} +\frac{1}{4}

Factors of 10 = 5\times2

Factors of 100 = 5\times2\times5\times2

Factors of 4 = 2\times2

Therefore, the least common factor of 10, 100 and 4 is 100. With like denominators we can operate on just the numerators,

\frac{6\times10}{10\times10} +\frac{35\times1}{100\times1} +\frac{1\times25}{4\times1}\rightarrow\frac{60+35+25}{100}\rightarrow\frac{120}{100}

\Rightarrow\frac{120}{100}\rightarrow\frac{6}{5}

Which can also be written as 1\frac{1}{5}.

So, from the above calculation it can be said that Julian walked 1\frac{1}{5} \text{ miles }.

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3 years ago
What does (p + 7(-2) Equal To?
g100num [7]

Answer:

-5

Step-by-step explanation:

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4 0
3 years ago
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