Answer with explanation:
The equation of two curves are
y=8 sin x
y=8 cos x
The point of intersection of two curves are
→8 sin x=8 cos x
sinx = cos x

When you will look between points , 0 and
,the curve obtained is right angled triangle.
Now, rotate the curve that is right angled triangle along the line , y= -1, to obtain a shape similar or resembling with Right triangular prism.
Draw a circular disc in the right triangular prism , having radius =x,and small part on the triangle having length dx.dx varies from 0 to
.
Required volume of solid obtained

=8-4√2 cubic units
Answer:
16 oz, 12 oz, 4 oz
Step-by-step explanation:
Since 1 pound is equal to 16 ounces, and you can only use each weight once or not at all, you can determine how much is needed by simply adding.
2 pounds is equal to 32 ounces.
To achieve 32 ounces, you can use a 16 ounce weight, which will then bring the scale to need 16 ounces.
After this you can youse a 12 ounce weight, which brings it down to 4 ounces.
The last weight needed is the 4 ounce weight which will then level out the balance scale.
The number of the specimens would be in the culture after 5 minutes will be 7,962.62.
<h3>What is an exponent?</h3>
Consider the function:
y = a (1 + r) ˣ
Where x is the number of times this growth occurs, a = initial amount, and r = fraction by which this growth occurs.
A bacteria culture grows at a rate of 20% per minute.
If the culture initially has 3,200 bacteria specimens.
Then the equation will be
y = 3200 (1 + 0.2) ˣ
y = 3200 (1.20) ˣ
Then the number of the specimens would be in the culture after 5 minutes will be
y = 3200 (1.20)⁵
y = 7962.62
More about the exponent link is given below.
brainly.com/question/5497425
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I think n is 9 hope i helped
Answer:
i)16
ii)9
Step-by-step explanation:
![\sqrt{256} \\=\sqrt{16*16} \\=16\\\\ii)\ \sqrt[3]{729}\\ =\sqrt[3]{9*9*9} \\=9](https://tex.z-dn.net/?f=%5Csqrt%7B256%7D%20%5C%5C%3D%5Csqrt%7B16%2A16%7D%20%5C%5C%3D16%5C%5C%5C%5Cii%29%5C%20%5Csqrt%5B3%5D%7B729%7D%5C%5C%20%3D%5Csqrt%5B3%5D%7B9%2A9%2A9%7D%20%5C%5C%3D9)