Answer:
Actually it's not polygon. it's a nonagon. With r=8.65mm″, the law of cosines gives us side a:
a=√{b²+c²−2bc×cos40°}
a=√{149.645−149.645cos40°}
Area Nonagon = (9/4)a²cos40°
=9/4[149.645−149.645cos40°]cot20°
=336.70125[1−cos(40°)]cot(20°)
Applying an identity for the cos(40°) does not get us very far…
= 336.70125[1−(cos2(20°)−1)]cot(20°)
= 336.70125[2−cos2(20°)]cot(20°)
= 336.70125[2−(1−sin2(20°))]cot(20°)
= 336.70125[1+sin2(20°)]cos(20°)sin(20°)
= 336.70125[cot(20°)+sin(20°)cos(20°)]mm²
The answer is 7 :) Hope this helps
Answer:
it would be 9/12
Step-by-step explanation:
if you want to get a denominator of 12 you would have to multiply by 3 from both and you should get 9/12. 3*3=9 and 4*3=12.
Answer:
A. 4
B. 1
Step-by-step explanation:
The degree of a one-variable polynomial is the largest exponent of the variable.
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<h3>A.</h3>
For f(x) = x^4 -3x^2 +2 and g(x) = 2x^4 -6x^2 +2x -1, the sum f(x) +a·g(x) will be ...
(x^4 -3x^2 +2) +a(2x^4 -6x^2 +2x -1)
= (1 +2a)x^4 +(-3-6a)x^2 +2ax -a
The term with the largest exponent is (1 +2a)x^4, which has degree 4. This term will be non-zero for a ≠ -1/2.
The largest possible degree of f+ag is 4.
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<h3>B.</h3>
The polynomial sum is ...
f+bg = (1 +2b)x^4 +(-3-6b)x^2 +2bx -b
When b = -1/2, the first two terms disappear and the sum becomes ...
f+bg = -x +1/2 . . . . . . a polynomial of degree 1
The smallest possible degree of f+bg is 1.
