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sergij07 [2.7K]
3 years ago
15

Could you help me understand cross sections of three-dimenstional object its harder than it sound.​

Mathematics
1 answer:
umka21 [38]3 years ago
5 0

A section, or cross-section, is a view of a 3-dimensional object from the position of a plane through the object. A section is a common method of depicting the internal arrangement of a 3-dimensional object in two dimensions. It is often used in technical drawing and is traditionally crosshatched.

Cross sections of three-dimensional objects are two-dimensional shapes of various sizes. They may be parallel to a side or base of the object or at an angle to these surfaces. A cross section may resemble the shape of the object’s side or base, or it may have a completely different shape.

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The sum of 6 consecutive even numbers is <br> 270.<br> What is the second number in this sequence?
KonstantinChe [14]
Lets find all the numbers..

x (1st number)
x + 2 ( 2nd number)
x + 4 (3rd number)
x + 6 (4th number)
x + 8 (5th number)
x + 10 (6th number)

Now add all those expressions and set them equal to 270 because that is the total.

x + x + 2 + x + 4 + x + 6 + x + 8 + x + 10 = 270
6x + 30 = 270
6x = 240
x = 40

Now we will substitute 40 for x in the expression of the second number.

x + 2
40 + 2
42

So the second number is 42

Hope this helps :)
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3 years ago
What is the slope of line y=-5
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The answer to your question is 0
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What is the value for ƒ(x) =
tia_tia [17]

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3 years ago
Use the following scenario for the next 4 questions: Based on the results of an annual customer satisfaction survey of State Far
forsale [732]

Answer:

Since the pvalue of 0.0985 > 0.05, we cannot infer that the satisfaction rate is less than the claim with a level of significance of 5%

Step-by-step explanation:

The null hypothesis is:

H_{0} = 0.9

Because tate Farm claims that policyholders have a customer satisfaction rate of greater than 90%.

The alternate hypotesis is:

H_{1} < 0.9

Because of the question: Can we infer that the satisfaction rate is less than the claim with a level of significance of 5%.

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

State Farm claims that policyholders have a customer satisfaction rate of greater than 90%.

This means that \mu = 0.9, \sigma = \sqrt{0.9*0.1}

To check the accuracy of this claim, a random sample of 60 State Farm policyholders was asked to rate whether they were satisfied with the quality of customer service.

This means that n = 60

Fifteen percent of these policyholders said they were not satisfied with the quality of service.

So 100 - 15 = 85% were satisfied, which means that p = 0.85

Test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.85 - 0.9}{\frac{\sqrt{0.9*0.1}}{\sqrt{60}}}

z = -1.29

z = -1.29 has a pvalue of 0.0985.

Since the pvalue of 0.0985 > 0.05, we cannot infer that the satisfaction rate is less than the claim with a level of significance of 5%

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3 years ago
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