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Zinaida [17]
2 years ago
6

I have to describe the angles and the sides of the triangle I don't have a clue​

Mathematics
1 answer:
babymother [125]2 years ago
7 0

Answers:

  • 0 acute angles
  • 0 obtuse angles
  • 0 right angles
  • 0 sides of equal length

===========================================================

Explanation:

The smaller sides a = 3 and b = 4 add to a+b = 3+4 = 7 which does NOT exceed the third side c = 7.

Therefore, a+b > c is not true and a triangle cannot be formed. The sum of any two sides of a triangle must exceed the third side. Refer to the triangle inequality theorem for more information.

Since a triangle cannot be constructed with those side lengths, this means we'll have 0's for each of the boxes.

---------------

If your teacher made a typo and didn't mean to use those numbers, then let me know and I'll update my solution.

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shepuryov [24]

Answer:

<em>The maximum area of the second board must be (5x^2+3x-6) square inches.</em>

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The total area of two different size boards cannot exceed (7x^2-6x+2) square inches.

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Suppose, the area of the second board is  y square inches.

That means......

y+(2x^2-9x+8)\leq 7x^2-6x+2\\ \\ y\leq (7x^2-6x+2)-(2x^2-9x+8)\\ \\y \leq 7x^2-6x+2-2x^2+9x-8\\ \\ y\leq 5x^2+3x-6

So, the maximum area of the second board must be (5x^2+3x-6) square inches.

7 0
3 years ago
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