Answer:
Step-by-step explanation:
Assuming the system is solvable in the first place, create an augmented matrix of coefficients from the equations. Then put the matrix into reduced row echelon form.
Example is attached.
"Demonstrate by solving the following system."
You need to provide the system of equations.
D
Sq rt of 8 is sq rt of 4 times sq rt of 2
The area of the circle is 28 ft square.
The area of the triangle is 30 ft square.
Step-by-step explanation:
1) The area of the circle= π*r^2
where π= 3.14(default value) and "r" is the radius of the circle.
Here, Radius of the circle(r)= 3 ft
Area = 3.14*3*3
= 28.26 ft sq.= 28 ft sq(rounded to the nearest whole number)
2) The triangle has the base= 10 feet and height= 6 feet
The Area of the triangle= 1/2(b)(h)
where "b" is the base and "h" is the height of the triangle.
Substitute b=10 and h=6 ,
Area of triangle= 1/2(10 ft)(6 ft)= 60/2= 30 feet sq.
Answer:
The radius of cylinder is 14 inches
Step-by-step explanation:
Given that the volume of cylinder is 196π in² and the height is 1 in . The formula for it is V = πr²h. Then you can substitute the following value into the formula:
V = 196π
h = 1
196π = π × r² × 1
r² = 196π/π
r² = 196
r = 14 in
3(x-5), using the distributive property, we get 3x - 15
