M∠ADB + m∠BDC = m∠ADC [<span>angle addition postulate]
x + x + 10 = 60
2x + 10 = 60
2x = 60 - 10
2x = 50
x = 50/2
x = 25
a
m</span>∠ADB = x = 25°
b
m∠BDC = x + 10 = 25 + 10 = 35°
Cost = (3,500) * (1.04)^years
Cost = (3,500) * (1.04)^4
<span><span><span>Cost = (3,500) * 1.16985856
</span>
</span>
</span>
<span><span>Cost = </span>4,094.50</span>
1/5, 0.4, 1/2, 0.75
Just convert all of them to decimals first then it should be easy or you .
Answer:
y = 460 miles per hr
x = 500 miles per hr
Step-by-step explanation:
Let the planes be X any
Let their speeds be xmiles/hr and ymiles/hr respectively
x = y + 40 (assuming X is faster by 40miles/hr)
Distance travelled by X to meet Y = 0.75x
Distance travelled by Y to meet X = 0.75y
0.75x + 0.75y = 720 --------1
Put x = y + 40 in eqn 1
0.75(y+40) + 0.75y = 720
0.75y + 30 + 0.75y= 720
1.5y = 690
y = 460 miles per hr
x = 460 +40
= 500 miles per hr
There is 12 inches in a foot. Times inches by feet. You can pick a number for the feet and do trial and error until you get a number the closet to 55.
12 inches times 4 feet equals 48 inches.
12x4= 48
Now subtract 55 inches from 48 inches
55-48= 7 inches
So 4 feet and 7 inches tall
