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2 years ago

Simplify 6z^-7 (2) x² (4) ^4x^-4

Mathematics

2 answers:

Pachacha [2.7K]2 years ago

8 0

Step-by-step explanation:

First, subtract

from each side of the equation to put the equation in standard form:

−

We can now use the quadratic formula to find the solutions for

. The quadratic formula states:

For

, the values of

which are the solutions to the equation are given by:

−

√

−

(

)

⋅

Substituting:

for

−

for

gives:

−

√

−

(

⋅

−

)

⋅

−

√

−

(

−

)

−

√

−

√

−

√

⋅

−

√

−

√

−

√

−

√

−

√

and

−

√

Mademuasel [1]2 years ago

6 0

Answer:

Step-by-step explanation:

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Use the graph below to estimate the solution to the system of equations shown.

Mila [183]

Answer: The second choice is answer.

Step-by-step explanation:

<h3>The first line (Blue One)</h3>

$y=-x-3$ (Slope is -1 and intercepts y at -3)

<h3>The second one (Red One)</h3>

$y=2x-8$ (Slope is 2, to find y-intercept. Substitute x = 0 then we get -8) (For x-intercept, it's 4. Just substitute y=0 to get x-intercept.)

Because there are choices, it's easy to notice.

The first one, x = -4 and almost -5 which is not right. (x is around 1 almost 2.)

The second one, x = 1 and almost 2 is right.

The third one, x = -1 and almost -2 is not right (The intersection isn't even at -1 or any negative number for x-axis.)

The fourth one, just like the first one... x = 4 almost 5

<h3>Or solve the equations.</h3>

$y=-x-3\\y=2x-8$

Substitute y=2x-8 in y=-x-3

$2x-8=-x-3\\2x-8+x+3=0\\3x-5=0\\3x=5\\x=\frac{5}{3}\\(x=1\frac{2}{3})$

Look at the value of x then find the answer that matches the value of x.

Now for y, substitute x = 5/3 in y = -x-3 (or in 2x-8 if you want.)

$y=-\frac{5}{3} -3\\y=-\frac{5}{3} -\frac{9}{3} \\y=-\frac{14}{3} \\(y=-4\frac{2}{3} )$

So the answer is the second choice.

6 0

3 years ago

A man has 1 coins in his pocket, all of which are dimes and quarters. Aif the total value of his change is $2.75, how many dimes

VLD [36.1K]

Using a system of equations, it is found that there are 5 dimes and 9 quarters in his pocket.

<h3>What is a system of equations?</h3>

A system of equations is when two or more variables are related, and equations are built to find the values of each variable.

In this problem, the variables are given as follows:

Variable x: number of dimes in his pocket.

Variable y: number of quarters in his pocket.

He has a total of 14 coins, hence:

x + y = 14 -> y = 14 - x.

They are worth $2.75, hence, considering the value of each coin(dimes $0.1 and quarters $0.25), we have that:

0.1x + 0.25y = 2.75

Since y = 14 - x:

0.1x + 0.25(14 - x) = 2.75

x = (0.25*14 - 2.75)/0.15.

x = 5.

y = 14 - x = 14 - 5 = 9.

There are 5 dimes and 9 quarters in his pocket.

More can be learned about a system of equations at brainly.com/question/24342899

#SPJ1

4 0

1 year ago

If 5+20-22-3x = 10-2-2x + 5, what is the value of x?<br> -3<br> -2<br> 2<br> 3

Olegator [25]

Answer:

-10

Step-by-step explanation:

3 0

2 years ago

Hamburgers cost $2.50 and cheeseburgers cost $3.50 at a snack bar. Ben has sold no more than $30 worth of hamburgers and cheeseb

Irina18 [472]

Given 2.50x + 3.50y < 30.

Where x represent the number of hamburgers and y represent the number of cheeseburgers.

Now question is to find the maximum value of hamburgers Ben could have sold when he has sold 4 cheeseburgers.

So, first step is to plug in y=4 in the given inequality. So,

2.50x+3.50(4)<30

2.50x+14 <30

2.50x<30- 14 Subtracting 14 from each sides.

2.50x< 16

$\frac{2.50x}{2.50}$ Dividing each sides by 2.50.

x<6.4

Now x being number of hamburgers must be an integer , so tha maximum value of x can be 6,

thus x = 6 hamburgers

So, the maximum value of hamburgers Ben could have sold is 6*2.5=$15

Hope this helps!!

8 0

2 years ago

How do you calculate the midpoint of question e)? I am very desperate. please help

andrey2020 [161]

Answer:

(-1,-1)

Step-by-step explanation:

Midpoint equation: $(\frac{x_2+x_1}{2}, \frac{y_2+y_1}{2})$

= $(\frac{-5/2+1/2}{2},\frac{-1/2-3/2}{2} )$

= $(\frac{-2}{2},\frac{-2}{2})$

=(-1,-1)

Use the formula and plug it in :)

7 0

2 years ago

Simplify 6z^-7 (2) x² (4) ^4x^-4​

Simplify 6z^-7 (2) x² (4) ^4x^-4