1-A. About fifty people because the odds are 1/2 and half of 100 is fifty.
B. They would raise 3,000 cents if 100 people played the game because of half didn't win you would have 2,500 cents from what they paid and if half did win you would have 500 cents from having to pay for the prizes leaving only 10 cent from each person who won.
C. I do not think it is an effective game for raising money at a school party because even though the chance is 50:50 it does necessarily mean that half of the people will win and half will lose. Also if not a lot of people come to play your game it won't raise as much money.
2-A. If you flipped a coin 75 times you would expect to get heads 37 to 38 times. Because that is around half.
B. If you flipped a coin 75 you would expect to get heads 37 to 38 times because that is also around half.
C. No, you cannot conclude that the coin is not a fair coin. You have a fifty:fifty chance of getting it heads or tails. Just because the coin landed on heads more that tails does not necessarily make it unfair because every time you flip it it still has that fifty: fifty chance.
I hope this helps.
Answer:
q = −
1
\6
Step-by-step explanation:
q = −
0.1
6 ¯ 6
M = 98 = 7×K
98/7 = 7×K/7 = K
The appropriate choice is
d. 7x=98. Divide both sides by 7. Kendall had $14.
Answer:
24cb 18 hb
Step-by-step explanation:
Let's call C the number of cheese burger sold and H the number of hamburgers.
As the cheeseburger sold are 3/4 of hamburgers, we can represent with the following equation:
C= (3/4)H (equation 1)
The total of burgers sold are the total of cheeseburger plus the total of hamburgers, and the sum 42. The equation representing it is:
C + H = 42
Replacing C by its value of eq. 1:
(3/4)H + H = 42
(3/4)H + (4/4)H = 42
(7/4) H = 42
Dividing both sides by (7/4)
H = 42/(7/4)
H= 42*(4/7)
H= (42/7)*4
H= 6*4
H=24
Then, C is:
C=(3/4)H
C=(3/4)*24
C= 3*24/4
C=72/4
C=18
We can verify it summing C+H
C+H=24+18=42 verified!
