Question

Mateo had $98, which is 7 times as much money as Kendall had. How much money did Kendall have?Select the correct solution method below, where x represents Kendall’s money.
a.x – 7 = 98. Add 7 to both sides. Kendall had $105.
b.= 98. Multiply both sides by 7. Kendall had $686.
c.x + 7 = 98. Subtract 7 from both sides. Kendall had $91.
d.7x = 98. Divide both sides by 7. Kendall had $14.

Answer 1

M = 98 = 7×K
98/7 = 7×K/7 = K

The appropriate choice is
  d. 7x=98. Divide both sides by 7. Kendall had $14.

Answer 2

Answer:

d.  7x = 98. Divide both sides by 7. Kendall had $14.

Step-by-step explanation:

Here, x represents Kendall’s money.

Given,

Mateo had 7 times as much money as Kendall had.

Thus, the money of Mateo = 7 times of x

= 7x

But, Mateo had $ 98.

$\implies 7x = 98$

Which is the required equation,

Now, for finding the value of x we need to isolate x,

For this we will Divide both sides by 7,

$\frac{7x}{7}=\frac{98}{7}$

$x=14$

Hence, Kendall had $ 14.

⇒ Option d is correct.