Step-by-step explanation:
3(p2q + pq2 - pq) - 6pq + 3pq2 =
3[-20 × 2 + (-20) × 2 - (-20)] - 6 × (-20) + 3 × 2 × (-20) =
3[-40 + (-40) + 20] - 6 × (-20) + 3 × 2 × (-20) =
3(-40 - 40 + 20) - 6 × (-20) + 3 × 2 × (-20) =
3(-80 + 20) - 6 × (-20) + 3 × 2 × (-20) =
3 × (-60) - 6 × (-20) + 3 × 2 × (-20) =
-180 + 120 + 6 × (-20) =
-180 + 120 + (-120) =
-180 + 120 - 120 =
-60 - 120 = -180
The awnsser is 9..................
Answer:
There's no question buddy
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Define x :
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Let the smallest number be x.
The other two numbers will be x+1 and x+2.
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Construct equation :
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The sum of all 3 numbers is 78
⇒ x + x + 1 + x + 2 = 78
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Solve x :
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x + x + 1 + x + 2 = 78
3x + 3 = 78
3x = 78 - 3
3x = 75
x = 25
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Answer: Smallest number = 25
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A^2+b^2=c^2
A=63
B=?
C=87
63^2+b^2=87^2
3969+b^2=7569
-3969 both sides
B^2=3600
Square root both sides
B=60in
