4 years ago

BRAINLIEST+40 POINTS

Mathematics

2 answers:

GarryVolchara [31]4 years ago

8 0

Answer:it would be : (15 times j)exponent of 15 times j to the 2nd power (15xjx2) plus 15

Step-by-step explanation:

Stupid Math

iren [92.7K]4 years ago

5 0

Answer:

Step-by-step explanation:

15j^2 + 15

the product of 15 and a number (j) squared increased by 15 ??

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Use synthetic division to find P (-10) for P(x)=2x^3+14x^2-58x

Savatey [412]

The polynomial remainder theorem states that the remainder upon dividing a polynomial $p(x)$ by $x-c$ is the same as the value of $p(c)$ , so to find $p(-10)$ you need to find the remainder upon dividing

$\dfrac{2x^3+14x^2-58x}{x+10}$

You have

..... | 2 ... 14 ... -58
-10 | ... -20 ... 60
--------------------------
..... | 2 ... -6 .... 2

So the quotient and remainder upon dividing is

$\dfrac{2x^3+14x^2-58x}{x+10}=2x-6+\dfrac2{x+10}$

with a remainder of 2, which means $p(-10)=2$ .