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3 years ago

Write 26 thousands 13 hundreds in standard form

Mathematics

2 answers:

bazaltina [42]3 years ago

4 0

Answer and Explanation:

To find : Write 26 thousands 13 hundreds in standard form?

Solution :

Standard form means writing a word in a number form according to place value system.

Thousand means 1000.

26 thousand means 26000.

Hundred means 100.

13 hundred means 1300.

So, 26 thousands 13 hundreds means 26000+1300=27300.

i.e. twenty seven thousand and three hundred.

Rudiy273 years ago

3 0

26,130 that's how you write it in standard.

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just olya [345]

Part A)

Given

Slope m = 6

Point (7, 2)

Using the point-slope form of the line equation

$y-y_1=m\left(x-x_1\right)$

where

m is the slope of the line

(x₁, y₁) is the point

In our case:

m = 6

(x₁, y₁) = (7, 2)

substituting the values m = 6 and the point (x₁, y₁) = (7, 2) in the point-slope form of the line equation

$y-y_1=m\left(x-x_1\right)$

$y - 2 = 6(x-7)$

Therefore, the equation in point-slope form for the line having the slope m = 6 and containing the points (7,2) will be:

$y - 2 = 6(x-7)$

Part B)

Given

Slope m = -3

Point (3, 8)

Using the point-slope form of the line equation

$y-y_1=m\left(x-x_1\right)$

where

m is the slope of the line

(x₁, y₁) is the point

In our case:

m = -3

(x₁, y₁) = (3, 8)

substituting the values m = -3 and the point (x₁, y₁) = (3, 8) in the point-slope form of the line equation

$y-y_1=m\left(x-x_1\right)$

$y - 8 = -3(x-3)$

Therefore, the equation in point-slope form for the line having the slope m = -3 and containing the points (3, 8) will be:

$y - 8 = -3(x-3)$

3 0

3 years ago

Select the graph for the solution of the open sentence. Click until the correct graph appears. |x| > 3/2

Soloha48 [4]

ANSWER

See attachment

EXPLANATION

The given inequality is

$|x| \: > \: \frac{3}{2}$

This implies that,

$x\: > \: \frac{3}{2} \: or \: - x\: > \: \frac{3}{2}$

Multiply both sides of the second inequality by -1 and reverse the inequality sign.

$x\: > \: \frac{3}{2} \: or \: x\: < \: - \frac{3}{2}$

The graphical solution to this inequality is shown in the attachment.