MAM I NEED HELP WHAT DO I NEED TO PUT!!!!!

Mathematics

1 answer:

schepotkina [342]3 years ago

6 0

You need to add the dollar sign so it will look like $0.50 or you could put $.50

You might be interested in

Riley makes a mistake in step 2 while doing her homework. What was her mistake? StartFraction x Over x squared minus 5 x + 6 End

kobusy [5.1K]

Answer:

The answer is:

She used the wrong common denominator

Step-by-step explanation:

Solving the given equation

$\frac{x}{x^2-5x+6}+\frac{x}{x+3}\\\\Step 1: \frac{x}{(x-2)(x-3)}+\frac{x}{x+3}\\Step2: \frac{x}{(x-2)(x-3)}+\frac{x(x-2)}{(x-2)(x+3)}\\Step3:\frac{x(x+3)+x(x-2)(x+3)}{(x-2)(x-3)(x+3)}$

Lets consider the steps given in the question:

$Step2: \frac{x}{(x-2)(x+3)}+\frac{3(x-2)}{(x-2)(x+3)}$

$Step3: \frac{x+3(x-2)}{(x-2)(x+3)}\\$

Lets compare both solutions:

In the original solution, the denominator of first term is (x-2)(x-3)

In the solution given in the question, the denominator of first term is (x-2)(x+3).

So the mistake she did in step 2 was that she change the sign of 3 in (x-3) from negative to positive, due to which she gets the wrong common denominator shown in Step 3.

7 0

4 years ago

Read 2 more answers

What is the slope-intercept equation of the line that includes (0,7) and (3,10)?

maksim [4K]

$\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{7})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{10}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{10-7}{3-0}\implies \cfrac{3}{3}\implies 1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-7=1(x-0)\implies y-7=x\implies y=x+7$