If h is m above the ocean and your trying to find when the rocket reaches that ocean… as the function gives the height above the ocean at a given time, when the height equals 0 the rocket will have reached the ocean so solve for t when h=0. working out in the photo. i got t=48.88seconds
There's many properties you can use to find an unknown angle.
There are too many to lists but one core example would be an isosceles triangle that has two adjacent sides and angles.
Let's say that the sides of an isosceles triangle are any number "x"
now since two sides of the triangle are the same we can add these two x's together.
x+x = 2x
now the other side of the triangle can be anything you like. We can call it 4x for this example.
now if we add them all together we'll get 4x+2x=6x
Now since the angles of a triangle add up to 180 degrees
we can equate 6x=180 leaving x to be 30.
Now since x belongs to both sides of the triangle we can say that both angles are congruent as well because the two sides of the triangle are congruent. This is a known triangle law.
Since both angles are now 30 degrees this will leave us with 2(30) = 60
now if we subtract 180 - 60 we'll get 120 which is the remainder of the 3rd angle of the side that corresponds with 4x.
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10 & 12
x = 1st consecutive even number
x + 2 = 2nd consecutive even number
x + x + 2 = 22
2x + 2 = 22
2x = 20
x = 10
x + 2 = 12
10 and 12 are the two consecutive even numbers
Answer:
g(x) = x^2 -6x +9
Step-by-step explanation:
A function f(x) translated right h units and up k units will become ...
g(x) = f(x -h) +k
You want the function f(x) = x^2 to be translated right h=3 units, so it will become ...
g(x) = f(x -3) = (x -3)^2
g(x) = x^2 -6x +9
That is a 30 60 90 triangle
The "short" side (DE) equals the middle side (FE) times (1 / sq rt(3))
short side = 8 * sqrt(3) * (1 / sq rt(3) = 8
Hypotenuse (DF) is 2 times the short side which equals 16.
Source:
http://www.1728.org/trig2.htm
