sec(A) = 5/3 ⇒ cos(A) = 3/5
Angles A and C are complimentary (they sum to 90°), so
sin(C) = cos(A) = 3/5
since sin(90° - x) = cos(x) for all x, and in turn
csc(C) = 1/sin(C) = 5/3
Your voltmeter and your teacher are both right, but the water analogy of electricity can only go so far. One big drawback is that, unlike with water, there is no absolute voltage. .... Wherever you put the black lead is defined as "0V". .... flowing (i.e. the circuit is broken) you will not get this change in voltage.
In Florida they are protected and can't be hunted.
