Answer:
C. Byte pair encoding is an example of a lossless transformation because an encoded string can be restored to its original version.
Explanation:
Byte pair encoding is a form of encoding in which the most common pairs of consecutive bytes of data are replaced by a single byte which does not occur within the set of data.
For example, if we has a string ZZaaAb, it can be encoded if the pairs of string ZZ are replaced by X and the second pair by Y. So, our data now becomes XYAb.
To get our original data, that is decode it, we just replace the data with the keys X = ZZ and Y = aa thus allowing our original data to be restored.
Since our original string is restored without loss of data, it implies that <u>byte pair encoding is an example of a lossless transformation because an encoded string can be restored to its original version.</u>
The first sentence that seems out of the logical order is the very first sentence, i.e, Also, she is moving the heavy oak bookcase to the bedroom.
A. 1
<u>Explanation:</u>
The fact that the sentence uses words like "she" and "also" leads to this conclusion. The logical order should move in a forward direction with the sentences forming a logical sequence.
The first sentence's structure is adding details to the actions which are already in progress and hence it should not be the first sentence. It should appear after the process of moving furniture has been started and further details are being added to it.
Marla can enter Food for examble for A11 on the exl page
Following are the program to calculate even digits sum:
<h3>Program:</h3>
#include <iostream>//header file
using namespace std;
int main()//main method
{
int a[10],s=0,i;//defining an array and an integer variable
cout<<"Enter array values: ";//print message
for(i=0;i<=9;i++)//defining a loop that input array value
{
cin>>a[i];//input array value
}
for(int i=0;i<=9;i++)//defining loop that check array value
{
if(a[i]%2==0)//defining if block that checks even number condition value
{
s=s+a[i];//adding even number value
}
}
cout<<"The sum of even number is: "<<s;//print even number sum value
return 0;
}
Program Explanation:
- Defining a header file.
- Defining the main method.
- Inside the main method, an integer array "a", and two integer variable "s,i" is declared.
- In the next step, a for loop is declared that input the array value, and after input value another loop is declared that check even number value in array.
- In this loop it adds array value and after adding the value a print method is declared that prints its value.
Output:
Please find the attached file.
Find out more information about the even number here:
brainly.com/question/4184435
