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Snowcat [4.5K]
2 years ago
5

Write (x+1)^5 in standard form?

Mathematics
2 answers:
Harman [31]2 years ago
6 0

Answer:

x^5 + 5

Step-by-step explanation:

standard form is just making is as distributed and simple as possible, so you distribute the exponent and then order the integers with the x at the beginning

noname [10]2 years ago
6 0

Answer:

x*x*x*x*x+1

Step-by-step explanation:

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1. A researcher tested the diastolic blood pressure of 15 marathon runners and 15 non-runners. The mean for the runners was 75.9
dlinn [17]

Answer:

Calculated value t =0.0109 < t = 1.701 at 28 degrees of freedom at 0.05 level of significance.

running a good way to lower a person's blood pressure

Step-by-step explanation:

<u>Step :1</u>

A researcher tested the diastolic blood pressure of 15 marathon runners and 15 non-runners

The first sample size is n₁ =15

The second sample size is n₂ =15

Given data the mean for the runners was 75.9 mm Hg with an SS of 1,500

The mean of the first sample x₁⁻ = 75.9 mm

The mean of the second sample x₂⁻   = 80.3mm

The standard deviation of the first sample (S₁) = 1,500

The standard deviation of the second sample (S₂) = 8

<u>Step 2</u>:-

<u>Null hypothesis </u>:- H₀ :  x₁⁻ = x₂⁻

<u>Alternative hypothesis</u>:- H₁ :  x₁⁻ ≠ x₂⁻

<u>level of significance</u> :- α= 0.05

The test statistic t = \frac{x_{1}^- -x_{2}^-  }{S\sqrt{\frac{1}{n_{1} } +\frac{1}{n_{2} } } }

where S^{2} =\frac{n_{1}S_{1} ^2+n_{2}S_{2} ^2 }{n_{1}+n_{2}-2}

n₁ =15 ,n₂ =15 x₁⁻ = 75.9 mm ,x₂⁻   = 80.3mm and (S₁) = 1,500 and (S₂) = 8

substitute all values in above equation, we get

S^{2} =\frac{15X(1500) ^2+15X(8) ^2 }{15+15-2}

s^2 = 1,205,391.42

Standard deviation = √1,205,391.42 = 1097.903

<u>Step 3</u>:-

The test statistic

                 t = \frac{x_{1}^- -x_{2}^-  }{S\sqrt{\frac{1}{n_{1} } +\frac{1}{n_{2} } } }

x₁⁻ = 75.9 mm ,x₂⁻   = 80.3mm, n₁ =15 ,n₂ =15 and S = 1097.903

The test statistic value t = -0.01097

modulus t = 0.0109

Calculated value t =0.0109

The degrees of freedom γ=n₁+n₂ -2 = 15+15 -2 =28

From t- distribution table

From tabulated value t = 1.701 at 28 degrees of freedom at 0.05 level of significance.

Calculated value t =0.0109 < t = 1.701 at 28 degrees of freedom at 0.05 level of significance.

Therefore we accepted null hypothesis.

running a good way to lower a person's blood pressure

   

3 0
3 years ago
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