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fgiga [73]
3 years ago
9

WILL MARK BRAINLEAST 100% 20 POINTS

Mathematics
2 answers:
mario62 [17]3 years ago
4 0

Answer:

16

Step-by-step explanation:

everything simplified is 16

Yuki888 [10]3 years ago
3 0

Answer:

16

Step-by-step explanation:

To simplify, we have to start from the innermost parentheses and expand from there!

-3+{1-3[20+2(-6-7)]}  -6-7=-13

-3+{1-3[20+2(-13)]}    2*-13=-26

-3+{1-3[20-26]}          20-26=-6

-3+{1-3[-6]}                 -3*-6=18

-3+{1+18}                     1+18=19

-3+19                           -3+19=16

16

I really hope this helps!! Have a wonderful day C:

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Alika [10]
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3 years ago
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Enter the value of n so the expression (-6y+1)+(4.7y-3.1) is equivalent to (ny-2.1)
Greeley [361]

If im correct, n= -1.3

7 0
3 years ago
Sandy has 16 roses,8 daisies, and 32 tulips. She wants to arrange all the flowers in bouguets. Each bouguet has the same number
avanturin [10]

Answer:

Greatest number of flowers that can be used in a bouquet is 8.

Step-by-step explanation:

In this question greatest number of flowers used in a bouquet will be decided by the "Greatest Common Factor" of the numbers of the flowers given.

So, factors of 16 = 1×2×2×2×2

Factors of 8 = 1×2×2×2

Factors of 32 = 1×2×2×2×2×2

Common factors = 1×2×2×2

Greatest Common Factor of these numbers will be = 1×2×2×2 = 8.

Therefore, greatest number of flowers that could be in a bouquet is 8.

3 0
3 years ago
Exhibit 18-2 Students in statistics classes were asked whether they preferred a 10-minute break or to get out of class 10 minute
tankabanditka [31]

Answer:

The mean and the standard deviation of the sampling distribution of the number of students who preferred to get out early are 0.533 and 0.82

Step-by-step explanation:

According to the given data we have the following:

Total sample of students= 150

80 students preferred to get out 10 minutes early

Therefore, the mean of the sampling distribution of the number of students who preferred to get out early is = 80/150 = 0.533

Therefore,  standard deviation of the sampling distribution of the number of students who preferred to get out early= phat - p0/sqrt(p0(1-p)/)

= 0.533-0.5/sqrt(0.5*0.5/15))

= 0.816 = 0.82

3 0
4 years ago
Read 2 more answers
Please help I’ll mark you as brainliest if correct
lara [203]
11 yeah Mark branliest
3 0
3 years ago
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