Given:
Angle A = 18.6°
Angle B = 93°
Length of side AB = 646 meters
To find:
the distance across the river, distance between BC
Steps:
Since we know the measure of 2 angles of a triangle we can find the measure of the third angle.
18.6° + 93° + ∠C = 180°
111.6° + ∠C = 180°
∠C = 180° - 111.6°
∠C = 68.4°
Therefore the measure of angle C is 68.4°.
now we can use the law of Sines,
![BC[sin(68.4)] = 646 [sin(18.6)]](https://tex.z-dn.net/?f=BC%5Bsin%2868.4%29%5D%20%3D%20646%20%5Bsin%2818.6%29%5D)
meters
Therefore, the distance across the river is 222 meters.
Happy to help :)
If anyone need more help, feel free to ask
Y= 80.55% approximately, 80.6% rounded up
Calculations:
The percent (percentage) of a given number p/q can be found, for the most part, without a calculator by a slight change in the notation:
y=the number 29/36 expressed as a percent becomes
y=[29(2.7777777778 approx.)]/[36(2.7777777778 approx.)]
y=0.8055 approx. (Express the decimal numeral as a percent)
y=0.8055(100)
y=
80.55% approx., which is 80.6% rounded up to the nearest tenth percent
Answer:
it would round up too 27.30
Step-by-step explanation:
Step-by-step explanation:
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