Ask question

Ask question

All categories

3 years ago

6

Help with these plz. a.

1 answer:

Murljashka [212]3 years ago

6 0

Answer:

3= A

2=A or D I am not sure

Step-by-step explanation:

You might be interested in

Find the approximate area of a circle with radius equal to 8 ft. (Use = 3.14.)

Tcecarenko [31]

The area of a circle is given by

$A=\pi r^2$

If you want to approximate pi with 3.14, the formula becomes

$A = 3.14\times 8^2 = 3.14 \times 64 = 200.96$

8 0

4 years ago

Two dice are rolled. Define the events as follows: A : sum of 7, B : doubles, C : sum of 8

love history [14]

Answer: for a sum of 7 would either be 6 and 1, 5 and 2 or 4 and 3. you can roll a double 1,2,3,4,5,6. the sum of 8 would be 2 and 6, 3 and 5 and a double 4,

Step-by-step explanation:

well the there are six sides on a die so 6 x 2 is 12 so the max sum you can get is 12. So you take 7 and you start adding up to 7, same thing for sum of 8. since there is 6 sides and a pair of dices you will roll six doubles

5 0

3 years ago

Find an equation of the set of all points equidistant from the points A(−3, 6, 3) and B(4, 1, −1). Describe the set.

valentinak56 [21]

Answer:

See below

Step-by-step explanation:

I will describe this set in R³. Let P=(x,y,z) be a point equidistant to A and B, that is, the distance from P to A is equal to the distance from P to B.

First, using the usual distance formula, the distance from P to A is equal to $d(P,A)=\sqrt{(x-(-3))^2+(y-6)^2+(z-3)^2}=\sqrt{(x+3)^2+(y-6)^2+(z-3)^2}$

On the other hand, the distance form P to B is equal to $d(P,B)=\sqrt{(x-4)^2+(y-1)^2+(z-(-1))^2}=\sqrt{(x-4)^2+(y-1)^2+(z+1)^2}$

P is equidistant from A and B if and only if P satisfies the equation d(P,A)=d(P,B), that is,

$\sqrt{(x+3)^2+(y-6)^2+(z-3)^2}=\sqrt{(x-4)^2+(y-1)^2+(z+-1)^2}$

Take the square in both sides of this equation to get

$(x+3)^2+(y-6)^2+(z-3)^2=(x-4)^2+(y-1)^2+(z+1)^2$

$(x+3)^2-(x-4)^2+(y-6)^2-(y-1)^2+(z-3)^2-(z+1)^2=0$

You can simplify using difference of squares and multiplying like this:

$(7)(2x-1)+(-5)(2y-7)+(-4)(2z-2)=0$

$14x-10y-8z+36=0$

which is the equation of a plane.

4 0

4 years ago

<img src="https://tex.z-dn.net/?f=%5Cleft%20%5C%7B%20%7B%7Bx%5E3%20%2Bx%5E2y%2Bxy%5E2%2By%5E3%3D0%7D%20%5Catop%20%7Bx%5E2%2B4y%5

zimovet [89]

The solution to the system of equations is (-1, 1) and (1, -1)

<h3>How to determine the solution to the system of equations?</h3>

The system of equations is given as:

x^3 + x^2y + xy^2 + y^3 = 0

x^2 + 4y^2 = 5

The equations in the above system of equations are nonlinear equations.

The best way to a system of equations that are nonlinear equations is by the use of graphs

So, we start by plotting the graphs of the equations in the system of equations given as x^3 + x^2y + xy^2 + y^3 = 0 and x^2 + 4y^2 = 5

See attachment for the graph

The point of intersection represents the solution

From the attached graph, the points of intersection of the equations are

(-1, 1) and (1, -1)

Hence, the solution to the system of equations is (-1, 1) and (1, -1)

Read more about system of equations at:

brainly.com/question/13729904

#SPJ1

8 0

2 years ago

Im supposed to find x for this arc but i don't really understand it

hram777 [196]

50 = 1/2 (20+ x)
100 = 20 + x
80 = x

answer
x = 80

3 0

4 years ago