Answer:
d. -19, -3.7, -3/4, 6.05
Step-by-step explanation:
Hope this helps mate (´▽`ʃ♡ƪ)
Since, population of species A is represented by : 
Let us find the population of species A, at the end of week 1:
i.e., x = 1
i.e., 
i.e., 
i.e., 
Also, since population of species B is represented by : 
Let us find the population of species B, at the end of week 1:
i.e., x = 1
i.e., 
i.e., 
i.e., 
Thus, at the end of 1 week, species A and species B will have the same population.
Hence, option D is correct.
<u>The commutative property is when you can change the order and it will be the same answer.</u>
<u>6 + 8 + 7 = 7 + 8 + 6</u> would be your answer.
Answer
a
Step-by-step explanation:
because submarine b has a bigger negative number so its more further down
Answer:
120.39ft²
Step-by-step explanation:
Hopefully that helps :)