If there is one table (t=1) then 6 chairs (c=6) can be placed around the table, 2 along the length on each side and 1 at each end.
When t=2, and the tables are end to end (joined at their width) c=10, that is, 4 chairs on each side of the double table and 1 at each end. Each time a table is added c increases by 4 so we can write c=4t+2 the constant 2 being the single chair at each end. If the tables are separated then c=6t.
Volume = (Area of the base)x(Height)
66.85 = 15(H)
66.85/15 = H
H = 4.4567
The height is 4.4567mm.
It is
(3-x)^2
i made sure it correct this time
F(x)=-3(x)+4
Therefore this implies that we must put the -4 where we see an X on the equation
F(-4)=-3(-4)+4
=16
Answer:
99.7% of the sample proportions will fall between 0.133 and 0.307.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 0.22
Standard deviation = 0.029
99.7% of the sample proportions will fall within which of the following intervals?
Within 3 standard deviations of the mean.
Lower end: 0.22 - 3*0.029 = 0.133
Upper end: 0.22 + 3*0.029 = 0.307
99.7% of the sample proportions will fall between 0.133 and 0.307.