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3 years ago

⚠️ HELP ⚠️⚠️ I don’t understand ⚠️

Mathematics

2 answers:

Scilla [17]3 years ago

5 0

Answer:

c and a are the correct answers

Pepsi [2]3 years ago

4 0

Answer:

A, B and C

Step-by-step explanation:

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Mrs. Byrne's class went raspberry picking. The data show the weights of the cartoons of raspberries the students picked. Make a

Licemer1 [7]

Here is what you tally chart/table would look like:

Weight Tallies

1/4 lll
2/4 ll
3/4 lll
4/4 l

Here is what your line plot would look like:

X X
X X X
<u>X X X X
</u><u />1/4 2/4 3/4 4/4

4 0

3 years ago

I round to 900 I have twice as many hundreds as ones and all my digits are different but their sums are 18 can someone answer th

stellarik [79]

Answer:

The number of once is 9.1

The number of hundreds is 8.9

Step-by-step explanation:

Given as :

The total of digits having ones and hundreds = 900

The sum of digits = 18

Let The number of ones digit = O

And The number of hundreds digit = H

So, According to question

H + O = 18 .........1

100 × H + 1 × O = 900 ........2

Solving the equation

( 100 × H - H ) + ( O - O ) = 900 - 18

Or, 99 H + 0 = 882

Or , 99 H = 882

∴ H = $\frac{882}{99}$

I.e H = 8.9

Put the value of H in eq 1

So, O = 18 - H

I.e O = 18 - 8.9

∴ O = 9.1

So, number of once = 9.1

number of hundreds = 8.9

Hence The number of once is 9.1 and The number of hundreds is 8.9

Answer

4 0

3 years ago

You separate 42 bulbs of garlic into two groups:one for planting and one for cooking. You will plant 3 bulbs for every 4 bulbs t

alexira [117]

Answer:

144 cloves

Step-by-step explanation:

You separate 42 bulbs of garlic into two groups:one for planting and one for cooking.

We have a ratio of planting to cooking

Planting : Cooking

You will plant 3 bulbs for every 4 bulbs that you will use for cooking.

Hence: 3 : 4

The total of their proportion = 3 + 4 = 7

Hence:

The number of garlic you plant =

3/7 × 42 = 18 bulbs of garlic

The number of garlic you use to cook =

4/7 × 42 = 24 bulbs of garlic

We are also told that:

Each bulb has about 8 cloves. How many cloves of garlic will you plant?

From the calculation above , we know the number of bulbs of garlic been planted

= 18 bulbs.

Hence:.

1 bulb = 8 cloves

18 bulbs = x

x = 8 cloves × 18 bulbs

x = 144 cloves

Therefore, you will plant 144 cloves of garlic

6 0

3 years ago

Marie plants 12 packages of vegetable seeds in a community garden. Each package costs $1.97. What is the total cost of the seeds

umka21 [38]

Answer:

$23.64

Step-by-step explanation:

Each package of seeds cost $1.97, and Maire bought and planted 12 packages. You would do 12 x 1.97 to get 23.64

8 0

3 years ago

Read 2 more answers

Try this hard Math Problem if you dare!!

Dennis_Churaev [7]

Answer:

a. $(x - 3)^2 + 16$

b. $8(x -7)^2$

c. $(a^2 - 1)(7x - 6)$ or $(a+1)(a-1)(7x-6)$

d. $(x^2-4)(x^2+3)$ or $(x-2)(x+2)(x^2+3)$

e. $(a^n+b^n)(a^n-b^n)(a^{2n} +b^{2n})$

Step-by-step explanation:

$a.\ (x + 1)^2 - 8(x - 1) + 16$

Expand

$(x + 1)(x + 1) - 8(x - 1) + 16$

Open brackets

$x^2 + x + x + 1 - 8x + 8 + 16$

$x^2 + 2x + 1 - 8x + 24$

Collect Like Terms

$x^2 + 2x - 8x+ 1 + 24$

$x^2 - 6x+ 25$

Express 25 as 9 + 16

$x^2 - 6x+ 9 + 16$

Factorize:

$x^2 - 3x - 3x + 9 + 16$

$x(x -3)-3(x - 3) + 16$

$(x - 3)(x - 3) + 16$

$(x - 3)^2 + 16$

$b.\ 8(x - 3)^2 - 64(x-3) + 128$

Expand

$8(x - 3)(x - 3) - 64(x-3) + 128$

$8(x^2 - 6x+ 9) - 64(x-3) + 128$

Open Brackets

$8x^2 - 48x+ 72 - 64x+192 + 128$

Collect Like Terms

$8x^2 - 48x - 64x+192 + 128+ 72$

$8x^2 -112x+392$

Factorize

$8(x^2 -14x+49)$

Expand the expression in bracket

$8(x^2 -7x-7x+49)$

Factorize:

$8(x(x -7)-7(x-7))$

$8((x -7)(x-7))$

$8(x -7)^2$

$c.\ 7a^2x - 6a^2 - 7x + 6$

Factorize

$a^2(7x - 6) -1( 7x - 6)$

$(a^2 - 1)(7x - 6)$

The answer can be in this form of further expanded as follows:

$(a^2 - 1^2)(7x - 6)$

Apply difference of two squares

$(a+1)(a-1)(7x-6)$

$d.\ x^4 - x^2 - 12$

Express $x^4$ as $x^2$

$(x^2)^2 - x^2 - 12$

Expand

$(x^2)^2 +3x^2- 4x^2 - 12$

$x^2(x^2+3) -4(x^2+3)$

$(x^2-4)(x^2+3)$

The answer can be in this form of further expanded as follows:

$(x^2-2^2)(x^2+3)$

Apply difference of two squares

$(x-2)(x+2)(x^2+3)$

$e.\ a^{4n} -b^{4n}$

Represent as squares

$(a^{2n})^2 -(b^{2n})^2$

Apply difference of two squares

$(a^{2n} -b^{2n})(a^{2n} +b^{2n})$

Represent as squares

$((a^{n})^2 -(b^{n})^2)(a^{2n} +b^{2n})$

Apply difference of two squares

$(a^n+b^n)(a^n-b^n)(a^{2n} +b^{2n})$

6 0

3 years ago