Answer:
By difference in there ribosomal RNA sequence
Explanation:
Both bacteria and archaea lack membrane-bound nucleus and earlier both are considered in the same categories. Carl Woese was the scientist who discovered that bacteria and archaea are not similar.
Carl Woese and his lab members checked the ribosomal RNA in some archaeans and concluded that the archaeans are more closely related to eukaryotes than bacteria. After the study on archean Carl Woese classified the prokaryotes into two domains i.e., bacteria and archaea.
Therefore by difference in the ribosomal RNA sequence archaeons first distinguished from other prokaryotes.
Answer:
Cellulose is considered as complex carbohydrates
Explanation:
It is beacause usually it is found outside of the plant and it is so hard and rigid so it is hard to digest. They are usually used in making colths.
Answer: The correct answers are-
1) C) S Phase
2) A) prophase, metaphase, anaphase, telophase.
Cell cycle corresponds to the division of cell, which occurs primarily through two phases that are - Interphase ( which has G1, S, and G2 phase) during which cell grows, duplicates its genetic material and M ( mitotic phase) phase during which cell divides.
S phase ( synthesis phase) corresponds to the duplication of the genetic material (DNA). It takes place place after G1 ( Gap 1 phase) phase.
2) Mitosis is a type of cell divison in which one parent cell divides to produce two daughter cells with same number of chromosomes. Prophase is the first phase, followed by metaphase, anpahse, and telophase.
<span>Predict which species of finch would be most likely to survive if the weather on the Galapagos Islands gradually changed and the seeds available to the finches became larger with heavier coverings.
Answer: The </span><span>species of finch that would be most likely to survive are </span>Large Ground Finches because they have big, thick beaks to break the seed-heavy coverings.
Step 1
Glucose enters glycolysis pathway and glycolysis yields pyruvate, then pyruvate undergoes processing.
step 2
Pyruvate processing ;releases acetylCOA which joins the citric acid cycle.
Step 3
The citric acid cycle yields 2ATP and CO2 and also releases NADH and FADH2 to electron transport chain and chemiosmosis.
Step 4
Chemiosmosis and electron transport chain yields 25 ATP molecules and H2O Oxygen enters electron transport chain and osmosis.
